Probability

Chapter 14 · Mathematics · Class 10 28 min read

Why This Matters

Before a cricket match, the captains toss a coin. Why does everyone accept that as fair? Because a fair coin is just as likely to land heads as tails — neither team has an edge. That single, everyday idea is the whole heart of this chapter: when a few outcomes are equally likely, we can put an exact number on “how likely” each one is.

That number is a probability — a measure of chance that runs from 0 (never happens) to 1 (always happens). Weather forecasts, insurance premiums, the odds in a game, even whether a launched satellite is expected to fail — all of them rest on probability. Scientists, doctors and economists lean on it every day to make decisions when the future is uncertain.

In Class IX you found probabilities by doing the experiment many times and counting — tossing a coin 1000 times and seeing how often heads showed up. That’s powerful, but you can’t always repeat an experiment (you can’t relaunch a satellite a thousand times to estimate failure). This chapter takes a smarter route: when outcomes are equally likely, you can calculate the probability directly, without any experiment at all.

The Big Idea

When an experiment has a fixed list of equally likely outcomes, the theoretical (classical) probability of an event E is simply a count: P(E) = (number of outcomes favourable to E) / (total number of possible outcomes). Every probability lies between 0 and 1: an impossible event has probability 0, a sure event has probability 1. And the chance of E not happening fills in the rest: P(not E) = 1 − P(E).

Let’s Break It Down

What theoretical probability is

First, two words we’ll use a lot. An experiment is an action with more than one possible result (tossing a coin, throwing a die, drawing a card). Each possible result is an outcome. An event is any collection of outcomes we care about — like “getting an even number” on a die, which is the three outcomes 2, 4 and 6.

The whole method rests on one assumption: the outcomes are equally likely — no outcome is favoured over another. A fair coin (we say unbiased), a fair die, a well-shuffled deck — all give equally likely outcomes. When that holds, Pierre-Simon Laplace’s 1795 definition gives the probability of an event E directly:

P(E) = (number of outcomes favourable to E) / (total number of all possible outcomes)

That’s it — favourable divided by total. No experiment needed. For one toss of a coin, the two equally likely outcomes are Head and Tail; the event “head” has 1 favourable outcome out of 2, so P(head) = 1/2 and likewise P(tail) = 1/2.

Probability from a single die

A fair die is thrown once. Find (i) P(getting a number greater than 4) and (ii) P(getting a number less than or equal to 4).

An event with only one outcome is called an elementary event — like “getting a head”, or “the die shows 3”. A neat fact: the probabilities of all the elementary events of an experiment add up to 1. For the die, P(1) + P(2) + … + P(6) = 1/6 × 6 = 1.

The 0-to-1 range: sure and impossible events

The favourable count can never be smaller than 0 or larger than the total, so every probability is squeezed between 0 and 1:

0 ≤ P(E) ≤ 1

The two extremes have names. An impossible event can never happen, so it has 0 favourable outcomes and P = 0. Throwing a single die and getting an 8 is impossible — no face is marked 8 — so P(getting 8) = 0/6 = 0. A sure (or certain) event always happens, so every outcome is favourable and P = 1. Getting a number less than 7 on a die is certain — all six faces qualify — so P(less than 7) = 6/6 = 1.

The range of probability values
Type of eventFavourable outcomesProbability
Impossible event0 (none)P(E) = 0
An ordinary eventsome, but not all0 < P(E) < 1
Sure / certain eventall of themP(E) = 1
Concept check

A bag holds only lemon-flavoured candies. You draw one without looking. What is the probability it is (a) orange-flavoured, (b) lemon-flavoured?

Complementary events: P(not E) = 1 − P(E)

For any event E, there’s a partner event “not E” — everything that is not in E. We write it E̅. Together E and E̅ cover all the outcomes with no overlap, so their probabilities must add to the whole:

P(E) + P(not E) = 1, which rearranges to P(not E) = 1 − P(E).

E and E̅ are called complementary events. This little formula is a huge shortcut: often the event you want is messy to count directly, but its complement is easy. Instead of counting that, count the complement and subtract from 1.

For example, drawing a card from a deck, P(not an ace) is tedious to count outcome by outcome — but there are 4 aces in 52 cards, so P(ace) = 4/52 = 1/13, and therefore P(not an ace) = 1 − 1/13 = 12/13. Much faster.

Using the complement

The probability that Sangeeta wins a tennis match is 0.62. What is the probability that her opponent Reshma wins? (Assume there is no draw.)

Worked examples: coins, dice and cards

These three setups appear again and again, so it pays to know each one’s outcome list cold. A coin has 2 outcomes (Head, Tail). A die has 6 (the faces 1 to 6). A standard deck has 52 cards in 4 suits of 13 — spades and clubs are black, hearts and diamonds are red; each suit runs ace, king, queen, jack, 10, 9, …, 2, and the kings, queens and jacks are the 12 face cards.

Two coins together

Two different coins are tossed at the same time. What is the probability of getting at least one head?

Drawing from a deck of 52

One card is drawn from a well-shuffled deck of 52 cards. Find the probability that it is (i) a red king, (ii) a face card, (iii) the queen of diamonds.

Now the classic two-dice problem. When two dice are thrown, an outcome is an ordered pair (first die, second die), so the pair 1-then-4 is different from 4-then-1. That gives 6 × 6 = 36 equally likely outcomes — best seen as a grid:

A 6 by 6 grid of all 36 outcomes for a blue die and a grey die. Rows are the blue die 1 to 6, columns the grey die 1 to 6. The five cells where the numbers add to 8 are highlighted along a diagonal: 2 and 6, 3 and 5, 4 and 4, 5 and 3, 6 and 2.
All 36 equally likely outcomes of two dice. The five highlighted cells are the ways the two numbers add to 8, so P(sum = 8) = 5/36.
Sum of two dice

Two dice are thrown together. Find the probability that the sum of the numbers on top is (i) 8, (ii) 13, (iii) less than or equal to 12.

Common Mistakes

⚠️ Common mistake
What students think

Any experiment with two results gives each result a probability of 1/2.

Why it seems right

Heads-or-tails and many textbook examples really do split 50-50, so 'two options means equal chance' feels like a safe default.

What actually happens

P = favourable/total only works when the outcomes are EQUALLY LIKELY. A bag with 4 red balls and 1 blue ball has two results (red or blue), but they are not equally likely — P(red) = 4/5, not 1/2. Always check that the outcomes are genuinely equally likely before counting.

⚠️ Common mistake
What students think

When two dice are thrown, the sums 2, 3, 4, ..., 12 are 11 equally likely outcomes, so each sum has probability 1/11.

Why it seems right

There are exactly 11 possible sums, so treating them as 11 equal outcomes looks tidy and natural.

What actually happens

The 11 sums are NOT equally likely. The equally likely outcomes are the 36 ordered pairs of faces. A sum of 7 happens 6 ways (6/36) while a sum of 2 happens only 1 way (1/36). Count the underlying equally likely outcomes, not the sums.

⚠️ Common mistake
What students think

To find P(at least one head) with two coins, you list the outcomes as 'two heads, two tails, or one of each' — three outcomes — so each has probability 1/3.

Why it seems right

'Two heads', 'two tails' and 'one of each' really are the three things that can happen, so calling them three equal outcomes seems reasonable.

What actually happens

'One of each' can occur two ways — (H, T) and (T, H) — so the equally likely outcomes are FOUR: (H, H), (H, T), (T, H), (T, T). 'One of each' has probability 2/4, not 1/3. Break compound outcomes back into the equally likely ones.

⚠️ Common mistake
What students think

P(not E) is just a different fraction you work out from scratch by counting; the value of P(E) doesn't help.

Why it seems right

Counting feels like the reliable method, so re-counting the complement seems safer than reusing a number you already have.

What actually happens

E and not-E are complementary: P(E) + P(not E) = 1, so P(not E) = 1 − P(E) ALWAYS. If P(ace) = 1/13, then P(not an ace) = 1 − 1/13 = 12/13 instantly — no need to recount 48 cards. Use the complement; it's faster and avoids errors.

Quick Check

A fair die is thrown once. What is the probability of getting an even number?

Which of these can NOT be the probability of an event?

If P(E) = 0.05, what is P(not E)?

One card is drawn from a well-shuffled deck of 52. What is the probability that it is a face card?

Practice Problems

Easy

easy

A bag contains 3 red balls and 5 black balls. A ball is drawn at random. Find (i) P(red) and (ii) P(not red).

easy

A die is thrown once. Find the probability of getting (i) a prime number, (ii) a number lying between 2 and 6.

Medium

medium

A box contains 90 discs numbered 1 to 90. One disc is drawn at random. Find the probability that it bears (i) a two-digit number, (ii) a perfect square, (iii) a number divisible by 5.

medium

A game of chance has a spinning arrow that comes to rest on one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (all equally likely). Find the probability that it points at (i) 8, (ii) an odd number, (iii) a number greater than 2.

Challenge

challenge

A game consists of tossing a one-rupee coin 3 times and noting the result each time. Hanif wins if all three tosses give the same result (three heads or three tails) and loses otherwise. Find the probability that Hanif loses the game.

challenge

A die is thrown twice. Find the probability that (i) 5 does not come up either time, (ii) 5 comes up at least once.

Summary

You should now be able to explain:

  • The theoretical (classical) probability of an event E is P(E) = (number of favourable outcomes) / (total number of all possible outcomes), provided the outcomes are equally likely.
  • The probability of a sure (certain) event is 1; the probability of an impossible event is 0.
  • Every probability lies in the range 0 ≤ P(E) ≤ 1.
  • An elementary event has just one outcome, and the probabilities of all elementary events of an experiment add up to 1.
  • For any event E, P(E) + P(not E) = 1, so P(not E) = 1 − P(E); E and not-E are complementary events, and the complement is often the quick way to an answer.
  • Know your outcome lists: a coin has 2 outcomes, a die has 6, two dice have 36 ordered pairs, and a deck has 52 cards (4 suits of 13, with 12 face cards).
  • Experimental probability (Class IX) comes from actually repeating trials; theoretical probability predicts the chance from assumptions. As the number of trials grows, the two get closer and closer.

What’s Next

This is the last chapter of your Class 10 Maths journey — and a fitting place to look back. Notice how it pulls together threads from across the year: the fractions and ratios behind every P(E), the careful listing and counting that echoes the logic of earlier chapters, and the comfort with 0, 1 and everything between that runs through real numbers and beyond. From Real Numbers and Polynomials to Linear Equations, Quadratics, Trigonometry, Coordinate Geometry, Areas and Volumes, Statistics and now Probability, each chapter has been one more tool for describing the world precisely. Probability is special because it lets you reason confidently even when you can’t be certain — exactly the situation in most real decisions. Keep applying this maths: estimate, model, check, and predict. You now have a full toolkit — go use it.