Light — Reflection and Refraction

Chapter 9 · Science · Class 10 58 min read

Why This Matters

Look into the back of a steel spoon. You look upright, but tiny. Dip a pencil into a glass of water. It looks broken at the water’s surface. A coin at the bottom of a bucket looks closer to the top than it really is. Your car’s side mirror even says “objects are closer than they appear.”

All of these happen because light does just two things. It bounces off surfaces. This is called reflection. And it bends when it moves from one material into another. This is called refraction. The best part is that both follow exact rules. The rules are so exact that you can calculate where an image will form, how big it will be, and whether it is upright or upside-down. You only need two simple formulas.

This chapter is the science behind torches, shaving mirrors, magnifying glasses, cameras, telescopes, and the spectacles that millions of people wear. Once you get the sign rules right, the rest is just careful arithmetic.

The Big Idea

Before the new ideas, here is the one fact from earlier classes that everything in this chapter is built on.

Light travels in straight lines until it hits a surface. At a mirror it reflects — it bounces back, with the angle of incidence equal to the angle of reflection. When it passes into a new material it refracts — it bends, because its speed changes. Curved mirrors and lenses use these two rules to bring rays together or spread them apart. This forms images, and we find where those images are using the mirror formula and the lens formula.

Two ideas run through the whole chapter:

  1. Reflection bends light back. Refraction bends light as it passes through. Refraction happens only because light moves at different speeds in different materials.
  2. To do the maths without getting confused about “is this plus or minus?”, we use one strict set of rules — the New Cartesian Sign Convention. Learn it once, and every numerical becomes a simple, step-by-step job.

Let’s Break It Down

Reflection and the two laws

The rules of reflection lean on two words you have met before — “perpendicular” and “the normal”. Let’s get them crystal clear first.

When light hits a shiny, polished surface it bounces off. This bouncing follows two laws of reflection:

  1. The angle of incidence equals the angle of reflection. (The angle of incidence is the angle of the incoming ray. The angle of reflection is the angle of the bounced-off ray. We measure both from the normal — the line drawn straight out from the surface, at 90°, at the exact spot where the ray hits.)
  2. The incoming ray, the bounced-off ray, and the normal all lie flat on the same plane (the same flat sheet).

But why should the two angles come out exactly equal? There is a lovely reason: light always takes the quickest path. Say light has to leave a point A, touch the mirror, and reach your eye at B. Of all the bent paths from A to the mirror to B, the shortest one is the only one light actually takes. Here is the trick to find it. Mark a point B′ the same distance behind the mirror as B is in front of it (its mirror image). The straight line from A to B′ is the shortest possible distance — and it crosses the mirror at exactly one point. The real path A → that point → B is the same length as A → B′, because B and B′ are mirror-images. And at that crossing point, simple geometry of the two mirror-image triangles forces the incoming angle to equal the outgoing angle. So “shortest path” and “i = r” are the same rule, just described two ways.

Light from point A bounces off a flat mirror to reach the eye at B. A mirror-image point B-prime is marked the same distance behind the mirror. The straight line from A to B-prime is the shortest route and crosses the mirror at one point; the real bounced path A to that point to B is the same length. The two shaded triangles are mirror images of each other, so the incoming angle i equals the outgoing angle r.
Figure 9.1 — Why the angle of incidence equals the angle of reflection. Light starts at point A (top left), bounces off the flat horizontal mirror, and reaches your eye at B (top right). The real path is the red two-part line A to the mirror to B, with arrowheads showing the direction of travel. To find the shortest such path, mark B-prime (bottom right) as the mirror image of B, the same distance below the mirror as B is above it. The blue dashed straight line from A to B-prime is the shortest possible route and it crosses the mirror at exactly one point. Because B and B-prime are mirror images, the real bounced path is the same length as that straight line, so light really does take the shortest route. The two pale green triangles on either side of the hit point are mirror images of each other, which forces the incoming angle i to equal the outgoing angle r. The vertical dashed grey line is the normal.

A plane mirror is just a flat mirror. The image you see in it is:

  • virtual (you cannot catch it on a screen — more on this soon),
  • erect (the right way up),
  • the same size as you,
  • as far behind the mirror as you are in front of it, and
  • laterally inverted — left and right are swapped.

Lateral inversion is why “AMBULANCE” is written back-to-front on the front of an ambulance. When the driver ahead sees it in their mirror, the letters flip and read correctly.

Spherical mirrors — the vocabulary

A spherical mirror is a small piece cut out of a shiny ball (a sphere). There are two kinds:

  • Concave mirror — the shiny surface curves inward, like the inside of a spoon. It brings light rays together. We say it converges light.
  • Convex mirror — the shiny surface curves outward, like the back of a spoon. It spreads light rays apart. We say it diverges light.

Figure 9.2 below puts both mirrors side by side and labels the five key points you’ll use in every mirror problem.

Concave and convex mirrors side by side, showing the pole P on the mirror, the centre of curvature C, the principal focus F midway between P and C, and the principal axis through them. Parallel rays converge to F after a concave mirror and appear to come from F behind a convex mirror.
Figure 9.2 — The two kinds of spherical mirror, side by side, with the five key terms labelled. Panel (a), the concave (converging) mirror on the left, curves inward like the inside of a spoon: two green rays coming in parallel to the principal axis reflect off the blue mirror arc and the red reflected rays actually cross at the principal focus F, which sits in front of the mirror between the pole P (the centre of the mirror surface) and the centre of curvature C (the centre of the sphere the mirror was cut from). Panel (b), the convex (diverging) mirror on the right, curves outward like the back of a spoon: the parallel green rays reflect and spread apart, and their red dashed backward extensions appear to come from F behind the mirror, with C also behind the mirror. In both panels the horizontal grey line is the principal axis. The focal length f is the distance PF and the radius of curvature R is the distance PC, and for both mirrors f equals R divided by 2.

Learn these five terms — every problem uses them:

  • Pole (P): the centre point of the mirror’s surface.
  • Centre of curvature (C): the centre of the ball (sphere) that the mirror was cut from.
  • Radius of curvature (R): the distance from P to C.
  • Principal focus (F): the point where rays that come in parallel to the axis meet after reflecting (concave mirror), or the point they seem to come from (convex mirror).
  • Focal length (f): the distance from P to F.

The one relationship you must remember is f = R/2. The focus sits exactly halfway between the pole and the centre of curvature.

This is not a random rule — it falls straight out of the law of reflection, and you can see why with one ray. Take a ray coming in parallel to the axis and hitting the mirror at a point M. The normal there is the radius MC (it points to the centre of curvature C). The incoming ray and the radius make some angle θ; by i = r the reflected ray leaves at the same angle θ on the other side of the normal. Now look at the triangle MCF, where F is the focus. Its angle at C is θ (between the radius and the axis), and its angle at F is also θ (the incoming ray was parallel to the axis, so these are equal “alternate” angles). Two equal angles means the triangle is isosceles, so the two sides facing them are equal: FM = FC. For a ray close to the axis, M sits almost above the pole P, so FM is practically the same as FP. That gives FP = FC — meaning F is the exact midpoint of P and C. Half of R is f. That is the whole reason.

A ray parallel to the principal axis hits a concave mirror at point M near the axis. The normal at M is the radius to the centre of curvature C, so the angle of incidence equals angle MCP, which is theta. By the law of reflection the reflected ray makes the same angle theta and crosses the axis at the focus F. The angle at C and the angle at F in triangle MCF are both theta, so the triangle is isosceles and FM equals FC. For a ray near the axis FM is almost FP, so FP equals FC, placing F exactly halfway between P and C.
Figure 9.3 — The geometry proof that the focus sits halfway, so f equals R divided by 2. A red ray comes in parallel to the principal axis and hits the concave mirror arc at point M, near the axis (M is at top right, P the pole is on the axis at the right edge). The grey dashed line from the centre of curvature C through M is the normal at M, because the normal to a sphere is always its radius. The angle between the incoming ray and this normal equals angle MCP, marked theta at C. By the law of reflection the red reflected ray leaves at the same angle and crosses the axis at the focus F, marked in red between C and P. Inside the pale blue triangle MCF the angle at C and the angle at F are both theta (they are equal alternate angles because the incoming ray is parallel to the axis), so the triangle is isosceles and the two sides FM and FC are equal, both labelled in green. For a ray close to the axis the point M sits almost above P, so FM is almost equal to FP, which gives FP equals FC. So F is the exact midpoint of P and C, meaning the focal length f is half the radius R.

Why a curved mirror reflects the way it does

Here is a question that confuses many students. How do you know which way a ray bounces off a curved mirror? The good news is simple. A curved mirror follows the exact same law as a flat one — angle of incidence = angle of reflection. You just need to find the normal at the spot where the ray hits.

For a spherical mirror, the normal is very easy to find. It is the line drawn from the hit point straight back to the centre of curvature C (this line is a radius of the sphere). A radius always meets a sphere at a right angle (90°). So that radius is the normal at that point. Once you have the normal, you reflect the incoming ray so that i = r (angle in equals angle out). That fixes the direction of the bounced ray. No guessing needed.

Two rays parallel to the axis strike a concave mirror at different heights. At each point the normal is drawn as a dashed radius back to the centre of curvature C. Applying angle of incidence equals angle of reflection about that normal, both reflected rays cross the axis at the focus F.
Figure 9.4 — How a curved mirror obeys i equals r at every point. Two red rays come in parallel to the principal axis at different heights and strike the blue concave mirror arc (the pole P is on the axis at the right). At each hit point the grey dashed line drawn back to the centre of curvature C is the normal there, because the normal to a spherical surface is just its radius, which meets the surface at 90 degrees. At each point the angle of incidence i equals the angle of reflection r about that dashed normal (i and r are marked near the upper hit point). The higher ray meets a normal that tilts more, so it reflects more steeply. Even so, both red reflected rays cross the axis at the same single point, the focus F, which lies between C and P. That is exactly why a concave mirror converges parallel light to one point.

Try this for several parallel rays. The further a ray is from the axis, the more its normal tilts. So each ray reflects a little more steeply, and they all cross at the same point — F. That is why a concave mirror brings light together. A convex mirror is the opposite. Its centre of curvature is behind the surface, so the normals point outward and the reflected rays spread apart. They look like they come from F behind the mirror. So whenever you are not sure which way a ray goes off a curved mirror, follow this rule: first draw the normal towards C, then apply i = r.

Real and virtual images — what’s the difference?

The words real and virtual appear in every row of the table below. So let’s be clear about what they mean. After a mirror or lens bends light, the rays do one of two things. They either actually meet at a point, or they only look like they come from a point.

  • A real image forms where the bounced (or bent) rays actually cross each other. Real light truly reaches that spot. So you can catch a real image on a screen (like a paper screen or a cinema screen). From a single mirror or lens, a real image always comes out upside-down (inverted).
  • A virtual image forms where the rays do not meet. The rays spread apart, and only their backward extensions (drawn as dashed lines in the diagrams) seem to meet — behind the mirror, or on the same side as the object for a lens. No real light reaches that spot. So you cannot catch a virtual image on a screen. You can only see it by looking into the mirror or lens. A virtual image is always the right way up (erect).

Here is the one-line test. Hold a paper screen where you think the image is. If a sharp picture lands on it, the image is real. If nothing lands on it, the image is virtual.

A side-by-side card comparing a real image and a virtual image. On the left a real image forms where solid rays actually cross, lands on a screen and is inverted, with negative magnification. On the right a virtual image forms where solid diverging rays only appear to meet at their dashed backward extensions, cannot be caught on a screen and is erect, with positive magnification.
Figure 9.5 — A side-by-side comparison of the two kinds of image. Panel (a), the REAL image on the left: two blue solid rays actually cross each other, real light reaches that crossing point, so a dark screen placed there catches a sharp picture. The green image arrow points downward, showing the image is inverted, and the magnification m is negative. Catching it on a screen works: YES. Panel (b), the VIRTUAL image on the right: the blue solid rays spread apart after the mirror or lens and never meet, so only their grey dashed backward extensions appear to meet at a point. No real light reaches there, so nothing lands on a screen. The red image arrow points upward, showing the image is erect, and the magnification m is positive. Catching it on a screen works: NO.

Real images around you:

  • The picture a cinema projector throws on the screen. (The film inside is loaded upside-down on purpose. That is because the real image it makes is inverted, so it lands the right way up on the screen.)
  • The image your camera forms on its sensor, and the image your eye forms on your retina. Both are real and inverted. (Your brain quietly flips it the right way up, so you never notice.)

Virtual images around you:

  • Your reflection in a flat bathroom mirror. It looks like “you” standing the same distance behind the glass. But there is only a wall back there. No light reaches that point, and you could never catch it on a screen. So it is virtual (and upright).
  • The enlarged word you see under a magnifying glass, and the wide view in a convex rear-view mirror or shop mirror. Both are virtual and upright.

Here is a link to the maths coming up. A negative magnification (m) means a real, inverted image. A positive m means a virtual, erect image. That one sign tells you the whole story.

Images in a concave mirror

A concave mirror is the interesting one. Its image changes completely depending on where you place the object. Here is the full picture:

Image formed by a concave mirror
Object positionImage positionSizeNature
At infinityAt FPoint-sizedReal, inverted
Beyond CBetween F and CDiminishedReal, inverted
At CAt CSame sizeReal, inverted
Between C and FBeyond CEnlargedReal, inverted
At FAt infinityHighly enlargedReal, inverted
Between P and FBehind the mirrorEnlargedVirtual, erect

Notice the pattern. As the object moves closer to the mirror, the image moves further away and gets bigger. This continues until the object crosses the focus. After that, the image flips to virtual, erect, and enlarged. (This is the shaving-mirror or make-up-mirror position.)

To find the image of a nearby object, you only need to draw two rays from the top of the object:

  1. One ray drawn parallel to the axis, which reflects back through F.
  2. One ray drawn to the pole P, which reflects back at the same angle on the other side of the axis.

The point where these two reflected rays cross is the top of the image.

One case is special and does not follow this “two rays from the top” method. That is a very distant object. Its light reaches the mirror as a parallel beam, instead of as rays spreading out from a nearby top (see Figure 9.6 below).

Object at infinity → a point image at F

Concave mirror with an object at infinity, shown as two parallel rays. They reflect off the mirror and converge to a point at the focus F. The image is a tiny real, inverted point at F.
Figure 9.6 — Image in a concave mirror when the object is at infinity. Because the object is extremely far away, its light arrives as a bundle of rays parallel to the principal axis (drawn as two horizontal rays coming in from the left). They strike the concave mirror arc and the reflected rays converge to a single point at the focus F, which lies on the axis between the pole P and the centre of curvature C. The image is therefore a tiny point at F: real, inverted, and highly diminished. This is how a reflecting telescope or solar cooker gathers far-off parallel light to one spot.

Why parallel rays from an object at infinity? Every point on an object sends out light in all directions. But the further away the object is, the less those rays have spread out by the time they reach the mirror. From something very far away — the Sun, a distant hilltop, a star — the rays from one point have travelled so far that they arrive almost perfectly parallel. (This is the same reason we treat sunlight as parallel beams.) So for an “object at infinity”, we do not draw two rays from a visible top. Instead we draw a bundle of parallel rays, and the concave mirror brings them all together at one point at F.

Real-life use: this is how a reflecting telescope and a solar cooker / solar furnace work. A large concave mirror gathers the almost-parallel rays from a faraway source and concentrates them at the focus.

Object beyond C → image between F and C

Concave mirror with the object placed beyond the centre of curvature C. A parallel ray reflects through F and a pole ray reflects symmetrically; they meet between F and C to form a real, inverted, diminished image.
Figure 9.7 — Image in a concave mirror when the object is beyond C. The green upright object arrow stands to the left of the centre of curvature C. Two rays are drawn from its top: the red ray parallel to the principal axis reflects off the mirror and passes back through the focus F, and the purple ray heads to the pole P and reflects symmetrically below the axis. The two reflected rays cross between F and C, and the orange image arrow there points downward below the axis. The image is real, inverted, and diminished (smaller than the object) — the small upside-down view you see standing well back from a shaving mirror.

Real-life use: this is the small, upside-down version of yourself you see when you stand well back from a concave shaving mirror. The same kind of small, real image is what a reflecting telescope’s main mirror forms of a far-off scene, before the eyepiece magnifies it.

Object at C → image at C (same size)

Concave mirror with the object at the centre of curvature C. The reflected rays meet back at C, forming a real, inverted image the same size as the object.
Figure 9.8 — Image in a concave mirror when the object is exactly at C. The green upright object arrow stands at the centre of curvature C. From its top, the red ray parallel to the principal axis reflects through the focus F, and the purple ray to the pole P reflects symmetrically. The two reflected rays cross back at C itself, where the orange image arrow points downward. The image forms at the same place as the object, the same size, but real and inverted. Because object and image sit together at C, this position is used in the lab to measure a concave mirror's radius of curvature.

Real-life use: since the object and its image sit together at C, this is a neat trick used in the lab to measure a concave mirror’s radius of curvature. Slide a screen until the sharp image lands right next to the object. That distance is R (and so f = R/2).

Object between C and F → image beyond C

Concave mirror with the object between C and F. The reflected rays meet beyond C to form a real, inverted, enlarged image.
Figure 9.9 — Image in a concave mirror when the object is between C and F. The green upright object arrow stands between the centre of curvature C and the focus F. From its top, the red ray parallel to the principal axis reflects through F, and the purple ray to the pole P reflects symmetrically below the axis. The two reflected rays cross beyond C, where the orange image arrow points downward. The image is real, inverted, and enlarged (bigger than the object) — the position used by a solar concentrator and a floodlight reflector.

Real-life use: a real and magnified image is useful in a solar concentrator (the dish in a solar cooker forms a large, intense, hot image of the Sun) and for the big bright spot a floodlight reflector throws onto a distant surface.

Object at F → image at infinity

Concave mirror with the object at the focus F. After reflecting, the two rays travel parallel to each other and never meet, so the image is formed at infinity.
Figure 9.10 — Image in a concave mirror when the object is exactly at the focus F. The green upright object arrow stands at F. From its top, the red ray parallel to the principal axis reflects through F, and the purple ray to the pole P reflects. After reflecting, the two rays come out parallel to each other and never cross, so no image forms at any normal distance — we say the image is at infinity. Run backwards, this is the torch and headlight case: a bulb placed at F sends out one strong parallel beam.

So is there an image, or not? When the reflected rays come out exactly parallel, they never actually cross. They would only “meet” infinitely far away. That is all “image at infinity” means: no real image forms that you could catch on a screen at any normal distance. This is the in-between case. It sits exactly between a real image (object beyond F) and a virtual image (object inside F). The useful part comes from doing the reverse trip: a bright bulb placed at F sends light out as that parallel beam. And if you look into such a mirror, your relaxed eye focuses the parallel rays onto your retina, so the source looks like it is infinitely far away.

Real-life use: run this case backwards. Put a bulb exactly at the focus, and the mirror sends every ray out as one strong parallel beam that barely spreads out with distance. That is exactly how torches, car headlights, searchlights, and lighthouse reflectors throw a beam that reaches far away.

Object between P and F → image behind the mirror

Concave mirror with the object between the pole P and the focus F. The reflected rays diverge; their dashed backward extensions meet behind the mirror to form a virtual, erect, enlarged image.
Figure 9.11 — Image in a concave mirror when the object is between the pole P and the focus F. The green upright object arrow stands close to the mirror, between P and F. From its top, the red ray parallel to the principal axis reflects through F, and the purple ray to P reflects. This time the reflected rays spread apart (diverge) and never meet in front of the mirror. Their dashed backward extensions meet behind the mirror, where the image arrow points upward. The image is virtual, erect, and enlarged — this is the shaving and make-up mirror position, where you see a bigger, right-way-up view of your own face.

Real-life use: you want a right-way-up and bigger view of your own face from close up. So this is the shaving / make-up mirror position. The same upright-and-magnified trick lets a dentist’s mirror show an enlarged view of a tooth.

Images in a convex mirror

A convex mirror is simpler. No matter where you put the object, the image is always virtual, erect, and diminished (smaller). It sits between P and F, behind the mirror. This wide, shrunk-down view is exactly why a convex mirror is used as a vehicle’s rear-view mirror. It shows a large area, even though everything looks smaller (which is why things seem “closer than they appear”).

Object at infinity → a point image at F (behind)

Convex mirror with parallel rays from a distant object. The rays reflect and diverge; their dashed backward extensions appear to come from the focus F behind the mirror, giving a virtual point image at F.
Figure 9.12 — Image in a convex mirror when the object is at infinity. The distant object's light arrives as rays parallel to the principal axis (coming in from the left). They strike the convex mirror arc and reflect outward, spreading apart (diverging). Their dashed backward extensions appear to come from the focus F, which lies behind the mirror, with the centre of curvature C further behind. The image is a virtual point at F: erect and highly diminished.

Object at a finite distance → image between P and F (behind)

Convex mirror with an object at a finite distance. A parallel ray and a pole ray reflect and diverge; their dashed backward extensions meet behind the mirror to form a small, upright, virtual image between P and F.
Figure 9.13 — Image in a convex mirror when the object is at a finite distance. The green upright object arrow stands in front of the convex mirror. From its top, the red ray parallel to the principal axis reflects as if it came from F behind the mirror, and the purple ray to the pole P reflects symmetrically. Both reflected rays diverge in front of the mirror, so their dashed backward extensions meet behind it, where the small orange image arrow points upward between P and F (the focus). The image is virtual, erect, and diminished. No matter where the object is, a convex mirror always gives this kind of small upright image, which is why it is used as a wide-view rear-view and side mirror.

Real-life use: because the image is always small and upright, a convex mirror fits a very wide area into a small piece of glass. This makes it perfect for vehicle rear-view / side mirrors (you can see several lanes at once), shop anti-theft mirrors, and mirrors placed at blind corners on roads and in corridors. The trade-off is that everything looks smaller, and so it looks further away. That is why the side mirror warns “objects are closer than they appear.”

Now that you’ve seen both mirrors in action, here’s a quick check to see if you can pick the right one for the job.

Concept check

Why is a concave mirror used in a torch or car headlight, but a convex mirror used as a side-view mirror?

The New Cartesian Sign Convention

Before doing any calculation, set up the rules for signs. Put the pole at the origin (the zero point), and lay the principal axis along the x-axis:

  • The object always sits on the left. So light travels from left to right.
  • Distances measured against the incoming light (to the left) are negative. Distances measured along the light (to the right) are positive.
  • Heights above the axis are positive. Heights below the axis are negative.
A labelled axis diagram of the New Cartesian Sign Convention. The pole P is at the origin where the mirror or lens stands, the principal axis is the horizontal x-axis, and the object is on the left with light travelling left to right. Distances measured to the left, against the light, are negative; distances to the right, along the light, are positive. Heights above the axis are positive and heights below are negative.
Figure 9.14 — The New Cartesian Sign Convention drawn as a set of axes. The pole P of the mirror or lens sits at the origin where the two axes cross, and the mirror or lens stands along the vertical line. The horizontal principal axis is the x-axis. A blue arrow at top left shows that light travels from left to right, and the green object arrow stands on the left. The rule for distances: anything measured to the LEFT, against the light (such as the object distance u), is negative, marked with a red minus on the left; anything measured to the RIGHT, along the light, is positive, marked with a green plus on the right. The rule for heights: heights ABOVE the axis are positive (green plus, top) and heights BELOW the axis are negative (red minus, bottom).

Here are the results you will use again and again. The object distance u is always negative (the object is on the left). A concave mirror’s focal length is negative (its F is in front). A convex mirror’s focal length is positive (its F is behind). For lenses: a convex lens has positive f, and a concave lens has negative f.

⚠️ Common mistake
What students think

Putting the object distance into a formula as a positive number, e.g. u = +25 cm.

Why it seems right

You measure the object distance as a plain length on a ruler — 25 cm — so writing it as a positive +25 feels completely natural.

What actually happens

In the sign convention, the object sits to the left of the mirror or lens, against the incoming light. So its distance is negative. Always write u = −25 cm for a real object. Then let the formula work out the signs of v and m for you.

Mirror formula and magnification

The mirror formula links the three distances:

1/v + 1/u = 1/f

Here u = object distance, v = image distance, and f = focal length. Magnification tells you how big the image is compared to the object:

m = h′/h = −v/u

Here h is the object’s height and h′ is the image’s height. A negative m means the image is real and inverted. A positive m means the image is virtual and erect.

Let’s put both formulas to work on a typical numerical, watching how the signs do all the heavy lifting.

Where does a concave mirror form the image?

An object 4.0 cm tall is placed 25.0 cm in front of a concave mirror of focal length 15.0 cm. Find the image distance, nature and size.

Refraction — why light bends

Now let’s look at the bending. When light passes from one see-through material into another at an angle, it changes direction. Why? Because its speed changes. Light is fastest in a vacuum (3 × 10⁸ m/s, which is 300 million metres per second). It slows down inside glass or water.

A rarer medium is one where light travels faster (like air). A denser medium is one where light travels slower (like glass).

  • Going from a rarer medium into a denser one (air → glass), light slows down and bends towards the normal.
  • Going from a denser medium into a rarer one (glass → air), light speeds up and bends away from the normal.

But why does a change in speed make light turn?

Slowing down by itself does not make something turn. A car braking in a straight line just goes slower; it does not move sideways. Light bends only when it crosses the boundary at an angle. The reason is surprisingly simple, once you stop picturing a single thin ray. Instead, picture a wide front moving forward together — like a row of soldiers marching in step, shoulder to shoulder.

Now march that row at an angle, off a hard road and onto soft mud. (Here the mud is the slower, denser medium.) They do not all reach the mud at the same moment. The soldiers at one end reach the mud first and slow down, while the others are still marching fast on the road. One end is now dragging, and the other end is racing ahead. So the whole row swings round — it changes direction, turning towards the mud. Later, when they step back onto firm road, the first ones to reach it speed up again, and the row swings back the other way.

A row of soldiers marching shoulder to shoulder crosses at an angle from a hard road onto soft mud. The end that reaches the mud first slows down and bunches closer together, while the far end is still striding fast on the road. Because one end drags and the other races ahead, the whole row swings round and the marching direction pivots toward the boundary.
Figure 9.15 — The marching-soldiers analogy for why light bends when it slows down. The diagram is split by a horizontal boundary: the upper pale region is hard road (fast, easy stride) and the lower shaded region is soft mud (slow, denser). A row of soldiers, drawn as a line of dots, marches shoulder to shoulder at an angle across the boundary. The end of the row that reaches the mud first slows down and the soldiers there bunch closer together, while the far end is still striding fast on the road. Because one end drags and the other races ahead, the whole row swings round, and the red arrow shows the marching direction pivoting toward the normal (the grey dashed vertical line). Light's wavefront does exactly this when it enters a slower medium.

Light’s wavefront does exactly this. Think of the front as the line of soldiers. The edge that enters the denser medium first slows down first, so the front pivots. It turns towards the normal when going into a slower medium, and away from the normal when coming back out. The fronts even crowd closer together in the slower medium (this is a shorter wavelength), just like the bunched-up soldiers.

A light wavefront crossing from air into glass at an angle. The wavefronts are drawn as parallel lines perpendicular to the ray; they are spaced wide apart in air where light is fast and crowd closer together in the slower, denser glass. The edge of each front that enters the glass first slows first, so the front pivots and the ray bends toward the normal. The refraction angle r is smaller than the incidence angle i.
Figure 9.16 — A real light wavefront crossing from air into glass, behaving just like the marching soldiers. The horizontal boundary separates air above (light travels fast) from glass below (slower, denser). The red ray crosses at an angle, and the short blue bars across it are the wavefronts, drawn perpendicular to the ray. In the air the fronts are spaced wide apart; in the glass they crowd closer together because light moves slower there (a shorter wavelength). The edge of each front that enters the glass first slows first, so the front pivots and the ray bends toward the normal (the grey dashed vertical line). The angle of refraction r in the glass is smaller than the angle of incidence i in the air.

It even explains a special case. If light hits the surface head-on (straight along the normal), the whole front slows down at the same moment. Nothing drags behind, so the ray goes straight through with no bend at all. This is exactly what you see when you look straight down into a pond.

Light hitting the surface head-on, straight along the normal. The wavefronts are parallel to the boundary, so the whole front crosses at the same instant and slows together. No edge reaches the slower glass before the other, nothing drags, and the ray passes straight through with no bend at all, even though it has slowed down.
Figure 9.17 — The special head-on case, showing why light hitting a surface straight on does not bend. The horizontal boundary separates air above from glass below. The red ray comes straight down along the normal (at 90 degrees to the surface). Now the blue wavefront bars are parallel to the boundary, so the whole front crosses at the same instant and slows together. No edge reaches the slower glass before the other, so nothing drags behind. The ray slows down but passes straight through with no bend at all. This is why looking straight down into a pond, things are not shifted sideways.

This is exactly why a pencil in water looks bent, why a pond looks shallower than it really is, and why a coin seems to “rise” when you pour water over it. Light from underwater bends as it leaves the surface. So the object appears to be in a slightly shifted place.

A ray of light passing through a rectangular glass slab. It bends towards the normal entering the glass (air to glass), travels straight inside, and bends away from the normal leaving the glass. The emergent ray is parallel to the incident ray but shifted sideways.
Figure 9.18 — A ray of light passing through a rectangular glass slab. The red incident ray comes in from the top left through air and hits the top face of the blue glass slab. Going from air into the denser glass it bends towards the normal (the grey dashed line at 90 degrees to the surface), as labelled. It travels in a straight line inside the glass, then at the bottom face it leaves the glass into air and bends away from the normal by the same amount. The result, the emergent ray at bottom right, is parallel to the original incident ray but shifted sideways. A faint dashed line marks the undeviated path the ray would have taken with no slab, so you can see the sideways shift.

Snell’s law and refractive index

How much the light bends follows the laws of refraction:

  1. The incoming ray, the bent (refracted) ray, and the normal all lie on the same plane.
  2. Snell’s law: for a given pair of materials, sin i / sin r is always the same fixed number. (Here i is the angle of incidence and r is the angle of refraction.) That fixed number is called the refractive index (n).

The refractive index compares the speed of light in two places. The (absolute) refractive index of a material is:

n = (speed of light in vacuum) / (speed of light in the material) = c/v

So water’s n = 1.33 means light travels 1.33 times faster in a vacuum than in water. A higher refractive index means the material is optically denser. That means light slows down more in it, and so it bends more.

Why a diamond’s huge n = 2.42 makes it sparkle

Diamond’s refractive index is 2.42. This is one of the highest of any everyday material, and that single number is why a diamond flashes in a way that plain glass never can. Two things work together:

  • Light gets trapped inside it. When light inside a dense material tries to escape out into the air, there is a limit. Past a certain steep angle — called the critical angle — the light cannot get out at all. Instead it reflects completely back inside. (This is called total internal reflection. You will study it properly in Chapter 10.) The bigger the refractive index, the smaller this critical angle. For diamond it is only about 24°, compared to about 42° for glass. So almost any ray that enters a diamond hits a back face too steeply to escape. It bounces around inside, and finally comes back out the top, towards your eye. A diamond is cut at carefully chosen angles, exactly so that this trapped light is sent straight back up. That bright, white sparkle is called the diamond’s brilliance.
  • It splits white light into colours. A high refractive index also bends different colours by different amounts. (Violet slows down and bends the most; red bends the least.) So each time light bends through the diamond, white light spreads out into a tiny rainbow. These coloured flashes are what jewellers call a diamond’s fire.

Glass (n is about 1.5) does both of these much more weakly. Its critical angle is larger, so more light just leaks out instead of bouncing back. That is why cut glass sparkles a little, but never as much as a real diamond.

⚠️ Common mistake
What students think

An optically denser medium must be heavier (more mass packed in).

Why it seems right

In everyday language, 'dense' means heavy. And the two often do go together — glass is both heavier and optically denser than air — so it feels natural to think 'optically denser' just means 'more mass packed in'.

What actually happens

Optical density is about how much a material slows light down, not about its mass. Kerosene has a higher refractive index than water (so it is optically denser), yet kerosene is lighter and floats on water. So optically denser just means a larger refractive index, which slows light more. It has nothing to do with weight.

Try a quick one to tie together bending direction and the speed formula n = c/v.

Concept check

Light goes from air into glass of refractive index 1.50. Does it bend towards or away from the normal, and what is its speed in the glass? (c = 3 × 10⁸ m/s)

Lenses — converging and diverging

A lens is a piece of see-through material with at least one curved surface. There are two types:

  • Convex (converging) lens — thicker in the middle. It brings parallel rays together at the focus. (A magnifying glass is a convex lens.)
  • Concave (diverging) lens — thinner in the middle. It spreads parallel rays apart, so they appear to come from the focus.

A convex lens has two foci (F₁ and F₂, one on each side). It also has a point at its centre called the optical centre (O). A ray that passes through O goes straight on without bending.

Why does the ray through O escape bending, when every other ray gets bent? Zoom right in on the middle of the lens. The front and back surfaces are curved overall, but at the very centre they are almost flat and parallel to each other — just like the two faces of a thin glass slab. And you already know what a parallel-sided slab does (see Figure 9.18 earlier): the ray bends towards the normal going in, then bends away from the normal by the same amount coming out. So it leaves parallel to how it came in — only shifted sideways a little. Because the lens is so thin, that sideways shift is almost zero. So the ray through O looks like it sails straight through without bending at all. That is the only ray you can trust to stay perfectly straight.

On the left, a convex lens with a ray passing through its optical centre O. On the right, a zoomed-in view of the centre shows the front and back faces are nearly flat and parallel, like a thin glass slab. The ray bends towards the normal entering and away from the normal leaving by the same amount, so it emerges parallel to its original direction, only shifted sideways. Because the lens is very thin the shift is almost zero, so the ray appears to go straight through.
Figure 9.19 — Why a ray through the optical centre O of a lens goes straight. Panel (a), on the left: a blue convex lens with a red ray passing through its optical centre O (the point at the very middle of the lens, on the axis). Panel (b), on the right: a zoomed-in view of the centre, where the front and back faces of the lens are almost flat and parallel to each other, just like the two faces of a thin glass slab. The red ray bends towards the normal entering the glass and away from the normal leaving it, by the same amount, so it comes out parallel to its original direction, only shifted sideways. Because a real lens is very thin, that sideways shift is almost zero, so the ray through O looks like it sails straight through without bending.

Why a lens bends light the way it does

A lens works by refraction, and it uses the same rule you saw with the glass slab. Entering the glass, light slows down and bends towards the normal. Leaving the glass, light speeds up and bends away from the normal. The normal at any point on a lens surface is just the line drawn at 90° to the surface there. On a curved surface, this normal tilts from point to point. That is what lets the lens bend different rays by different amounts.

The easiest way to see the result is to picture the lens as a stack of prisms. The top half of a convex lens is shaped like a prism with its thick base towards the axis. The bottom half is like a prism with its thick base towards the axis from below. A prism always bends light towards its thicker base. So the top half turns rays downward and the bottom half turns them upward — both towards the axis — so all the rays meet at F. A concave lens is the opposite. Its prisms have their bases pointing outward, so it spreads light apart.

A convex lens with a faint prism drawn in each half, base toward the axis. A ray through the top half bends downward and a ray through the bottom half bends upward, both toward the axis, meeting at the focus F. A ray through the optical centre passes straight through.
Figure 9.20 — A convex lens pictured as a stack of prisms, to show why it bends rays toward the axis. The blue convex lens stands on the principal axis, with a faint prism drawn in each half: the top-half prism has its thick base pointing down toward the axis, and the bottom-half prism has its thick base pointing up toward the axis. Because a prism always bends light toward its thicker base, the red ray entering the top half bends downward and the purple ray entering the bottom half bends upward, both turning toward the axis, so they meet at the focus F on the right. The green ray through the optical centre O passes straight through. A concave lens is the opposite: its prisms point their bases outward, so it spreads light apart.

So, just like with the mirror, you never have to guess. Find the normal to the surface, apply the bending rule (towards the normal going in, away from it coming out), and you will see that a convex lens always nudges rays towards the axis.

Images in a convex lens

Draw two rays from the top of the object:

  1. One ray parallel to the axis, which bends to pass through F₂.
  2. One ray through the optical centre O, which goes straight on.

The point where these two rays cross is the top of the image.

Object at infinity → a point image at F₂

A convex lens with parallel rays from a distant object. They converge to a point at F2, forming a real, inverted, highly diminished point image.
Figure 9.21 — Image in a convex lens when the object is at infinity. The distant object's light arrives as rays parallel to the principal axis, coming in from the left. They pass through the convex lens and converge to a single point at the far focus F₂ on the right. The image is a tiny point at F₂: real, inverted, and highly diminished. This is how a telescope objective or a burning glass focuses far-off parallel light onto one spot.

Real-life use: the objective lens of a refracting telescope (and of binoculars) collects the almost-parallel light from a distant star, planet, or hill. It brings that light to a sharp real image at its focus, which the eyepiece then magnifies. The same focusing of parallel rays lets a burning glass or a solar concentrator gather the Sun’s rays onto one tiny spot — hot enough to burn paper or boil water. Because the source is so far away, the image is basically just a point. That is the price of squeezing all that light into one place.

Object beyond 2F₁ → image between F₂ and 2F₂

A convex lens with the object beyond 2F1. The parallel ray bends through F2 and the central ray goes straight; they meet between F2 and 2F2 to form a real, inverted, diminished image.
Figure 9.22 — Image in a convex lens when the object is beyond 2F₁. The green upright object arrow stands to the left, beyond 2F₁. From its top, the red ray parallel to the principal axis bends at the lens and passes through the far focus F₂, and the purple ray through the optical centre O goes straight on. The two rays cross on the far side between F₂ and 2F₂, where the orange image arrow points downward. The image is real, inverted, and diminished. This is the camera, phone-camera, and human-eye case: a far-bigger scene shrunk to a real image that lands on the sensor or retina.

Real-life use: the camera — and the lens in your phone and even in your own eye (Chapter 10). The scene is far bigger than the sensor, the film, or the retina. So you need a real image (one that actually lands on the sensor) that is shrunk to fit. The exact image distance changes a little as the subject moves nearer or further away. So the camera re-focuses by sliding its lens. Your eye does the same job, but by changing the shape of its lens.

Object at 2F₁ → image at 2F₂ (same size)

A convex lens with the object at 2F1. The two rays meet at 2F2 to form a real, inverted image the same size as the object.
Figure 9.23 — Image in a convex lens when the object is at 2F₁. The green upright object arrow stands at 2F₁ on the left. From its top, the red ray parallel to the principal axis bends through the far focus F₂, and the purple ray through the optical centre O goes straight. The two rays cross at 2F₂ on the far side, where the orange image arrow points downward. The image is real, inverted, and the same size as the object. This is the 1:1 photocopier setting and the standard lab setup for measuring a convex lens's focal length.

Real-life use: a photocopier or scanner set to 1:1, where the copy must come out exactly the same size as the original. This special position is also the standard lab setup for measuring a convex lens’s focal length. Slide the object and the screen until the image is real, inverted, and the same size. The object distance you then measure is 2f, so f is half of that.

Object between F₁ and 2F₁ → image beyond 2F₂

A convex lens with the object between F1 and 2F1. The two rays meet beyond 2F2 to form a real, inverted, enlarged image.
Figure 9.24 — Image in a convex lens when the object is between F₁ and 2F₁. The green upright object arrow stands between the near focus F₁ and 2F₁. From its top, the red ray parallel to the principal axis bends through the far focus F₂, and the purple ray through the optical centre O goes straight. The two rays cross beyond 2F₂ on the far side, where the orange image arrow points downward. The image is real, inverted, and enlarged. This is the slide and cinema projector case: a small original thrown as a big real image on a distant screen, which is why slides are loaded upside-down so the picture lands the right way up.

Real-life use: the slide / film projector, the cinema projector, the overhead projector, and a photographic enlarger. All of these need a real image (so it can be caught on a distant screen or a sheet of paper) that is bigger than the small original. Because the image is inverted, slides and film are loaded upside-down on purpose, so the picture lands the right way up on the screen. The closer the slide moves towards F₁, the larger and further away the projected image becomes. That is why you move the projector back to fill a bigger screen.

Object at F₁ → image at infinity

A convex lens with the object at the focus F1. After the lens the rays emerge parallel to each other and never meet, so the image is at infinity.
Figure 9.25 — Image in a convex lens when the object is exactly at the focus F₁. The green upright object arrow stands at the near focus F₁. From its top, the red ray parallel to the principal axis bends through the far focus F₂, and the purple ray through the optical centre O goes straight. After the lens the two rays come out parallel to each other and never cross, so no image forms at any normal distance — the image is at infinity. Run backwards, this is how a searchlight, spotlight, or collimator made with a lens sends out a steady parallel beam.

Real-life use: run this case backwards. Put a bright source exactly at F₁, and the rays leave the lens as a parallel beam that barely spreads out however far it travels. This is how a searchlight, spotlight, or lighthouse beam made with a lens works. It is also how a collimator / condenser sends a steady parallel beam into spectrometers and other optical instruments. It is the lens version of putting a bulb at a concave mirror’s focus.

Object within F₁ → image on the same side (magnifying glass)

A convex lens with the object between the lens and F1. The rays diverge after the lens; their backward dashed extensions meet on the same side as the object to form a virtual, erect, enlarged image.
Figure 9.26 — Image in a convex lens when the object is within F₁ (the magnifying-glass case). The green upright object arrow stands between the lens and the near focus F₁. From its top, the red ray parallel to the principal axis bends through the far focus F₂, and the purple ray through the optical centre O goes straight. This time the two rays spread apart (diverge) after the lens and never meet on the far side. Their dashed backward extensions meet on the same side as the object, where the image arrow points upward, larger than the object. The image is virtual, erect, and enlarged. This is how a magnifying glass and a jeweller's loupe work.

Real-life use: the magnifying glass and the jeweller’s loupe. Hold the lens close so the object sits just inside F, and you see an upright, enlarged image that you can look straight at. Nothing is projected here. The magnified image is virtual and on the same side as the object, so it can only be viewed, never caught on a screen. This same “object just inside the focus” trick is how the eyepiece of a microscope or telescope enlarges the real image made by the first lens, and how a clip-on macro lens for a phone camera works.

Images in a concave lens

A concave (diverging) lens is the simplest of all. No matter where you put the object, the image is always virtual, erect, and diminished (smaller). It sits between the lens and F₁, on the same side as the object. The image barely changes as the object moves. It only shrinks a little and creeps closer to the lens. You build it with the same two rays: the parallel ray spreads out as if it came from F₁, and the central ray goes straight on. The image is where their backward extensions cross.

Object at infinity → a point image at F₁

A concave lens with parallel rays from a distant object. After the lens they diverge as if from F1; the image is a virtual point at F1.
Figure 9.27 — Image in a concave lens when the object is at infinity. The distant object's light arrives as rays parallel to the principal axis, coming in from the left. After passing through the concave lens they spread apart (diverge), and their dashed backward extensions appear to come from the near focus F₁, on the same side as the incoming light. The image is a virtual point at F₁: erect and highly diminished.

Object beyond 2F₁ → image between O and F₁

A concave lens with the object beyond 2F1. The diverging rays' backward extensions meet between O and F1 to form a small virtual, erect image.
Figure 9.28 — Image in a concave lens when the object is beyond 2F₁. The green upright object arrow stands far to the left, beyond 2F₁. From its top, the red ray parallel to the principal axis bends and diverges as if it came from the near focus F₁, and the purple ray through the optical centre O goes straight. The two real rays spread apart, so their dashed backward extensions meet between O and F₁, where the small orange image arrow points upward. The image is virtual, erect, and diminished.

Object at 2F₁ → image between O and F₁

A concave lens with the object at 2F1, forming a virtual, erect, diminished image between O and F1.
Figure 9.29 — Image in a concave lens when the object is at 2F₁. The green upright object arrow stands at 2F₁ on the left. From its top, the red ray parallel to the principal axis diverges as if from the near focus F₁, and the purple ray through the optical centre O goes straight. Their dashed backward extensions meet between O and F₁, where the small orange image arrow points upward. The image is virtual, erect, and diminished — barely changed from the other object positions, which is typical of a concave lens.

Object between F₁ and 2F₁ → image between O and F₁

A concave lens with the object between F1 and 2F1, forming a virtual, erect, diminished image between O and F1.
Figure 9.30 — Image in a concave lens when the object is between F₁ and 2F₁. The green upright object arrow stands between the near focus F₁ and 2F₁. From its top, the red ray parallel to the principal axis diverges as if from F₁, and the purple ray through the optical centre O goes straight. Their dashed backward extensions meet between O and F₁, where the small orange image arrow points upward. The image is virtual, erect, and diminished.

Object within F₁ → image very close to the lens

A concave lens with the object within F1, forming a virtual, erect, diminished image very close to the lens.
Figure 9.31 — Image in a concave lens when the object is within F₁. The green upright object arrow stands close to the lens, between it and the near focus F₁. From its top, the red ray parallel to the principal axis diverges as if from F₁, and the purple ray through the optical centre O goes straight. Their dashed backward extensions meet between O and the object, where the small orange image arrow points upward, very close to the lens. The image is virtual, erect, and diminished — confirming that a concave lens gives the same kind of small upright image wherever the object is placed.

Real-life uses — the same at every object position. A concave lens always makes the same kind of image — virtual, erect, and diminished — no matter where the object is. So all its uses depend on that one property, not on the object distance:

  • Spectacles for short sight (myopia). A short-sighted eye bends light too strongly and focuses distant objects in front of the retina. A concave lens spreads the incoming rays apart a little first. Then the relaxed eye can focus them correctly on the retina. (You will meet this again in Chapter 10.)
  • Door peephole (the “door viewer”). Its wide, small, always-upright image fits a whole hallway into a tiny hole. So you can see a broad view of who is outside, without opening the door.
  • Eyepiece of a Galilean telescope (and old opera glasses). A diverging eyepiece gives an upright view — unlike the upside-down view of a simple convex eyepiece. An upright view is what you want for looking at distant things on Earth.
  • Spreading a beam in optical systems. A concave lens is used to widen a narrow beam (a “beam expander” in lasers and projectors). It is also used as a correcting part inside good camera and binocular lenses, to keep the final image sharp.

In short, use a concave lens whenever you want a small, upright, wide view, or simply to spread light apart.

Lens formula, magnification and power

The lens formula looks like the mirror formula, but with a minus sign:

1/v − 1/u = 1/f

And the magnification for a lens is m = h′/h = v/u. (Note: there is no minus sign here, unlike with mirrors. Be careful not to mix them up.)

Here’s the lens formula in action — notice the minus sign and the plain m = v/u, so you don’t slip into the mirror version.

A convex lens used as a projector

A 2.0 cm tall object is placed 15 cm in front of a convex lens of focal length 10 cm. Find the image position, nature and size.

Finally, the power of a lens tells you how strongly it bends light:

P = 1/f (with f in metres), measured in dioptres (D).

A convex lens has positive power. A concave lens has negative power. For example, a +2.0 D lens is a convex lens with f = +0.50 m. When you place lenses together, their powers simply add up: P = P₁ + P₂ + … This is exactly how opticians stack test lenses on top of each other to find your eyeglass prescription.

Common Mistakes

⚠️ Common mistake
What students think

Using f = +15 cm for a concave mirror, just because 15 is a positive number.

Why it seems right

15 is written as a positive number, and f looks like just a length. So it feels natural to put it straight in as +15.

What actually happens

The sign of f comes from the rules, not from the number you are given. A concave mirror's focus is in front of it (on the left, against the light), so f is negative. The pattern: concave mirror and concave lens → f is negative; convex mirror and convex lens → f is positive. Decide the sign first, then put it in the formula.

⚠️ Common mistake
What students think

Using the mirror's magnification formula m = −v/u for a lens too.

Why it seems right

Mirrors and lenses use the same symbols m, v, and u, and their formulas look almost the same. So it is easy to think the same one works for both.

What actually happens

They are different. For a mirror, m = −v/u. For a lens, m = v/u (no minus). In the same way, the mirror formula adds (1/v + 1/u), but the lens formula subtracts (1/v − 1/u).

Quick Check

The radius of curvature of a concave mirror is 20 cm. What is its focal length?

No matter how far you stand from a certain mirror, your image is always erect. What kind of mirror could it be?

Which lens would you choose to read tiny dictionary print?

Practice Problems

easy

A convex mirror used as a rear-view mirror has a radius of curvature of 3.00 m. A bus is 5.00 m away. Find the position, nature and size factor of the image.

medium

An object 5 cm long is held 25 cm from a converging (convex) lens of focal length 10 cm. Find the position, size and nature of the image.

challenge

An object of size 7.0 cm is placed 27 cm in front of a concave mirror of focal length 18 cm. Where should a screen be placed for a sharp image? Find the size and nature of the image.

Summary

  • Light reflects off mirrors (angle of incidence = angle of reflection). It refracts (bends) when it passes between materials, because its speed changes.
  • Concave mirrors bring light together (converge); convex mirrors spread it apart (diverge). For both, the focal length is f = R/2.
  • A concave mirror’s image changes with the object’s position (real and inverted in most positions; virtual, erect, and enlarged when the object is inside F). A convex mirror’s image is always virtual, erect, and diminished.
  • Mirror formula: 1/v + 1/u = 1/f, and magnification m = −v/u. Always use the New Cartesian Sign Convention (object distance is negative; concave f is negative, convex f is positive).
  • Light bends towards the normal when entering a denser medium, and away from it when leaving. Refractive index n = c/v. A higher n means optically denser, which means it bends light more.
  • Convex lenses converge (f is positive); concave lenses diverge (f is negative). Lens formula: 1/v − 1/u = 1/f, and magnification m = v/u.
  • Power P = 1/f (with f in metres), measured in dioptres. Convex power is positive, concave power is negative. The powers of lenses placed together simply add up.

What’s Next

You now understand how a single mirror or lens bends light to form an image. But the most amazing optical instrument you own is your eye — a living convex lens that focuses all by itself. In Chapter 10: The Human Eye and the Colourful World, you will see how the eye forms images, why some people need the very spectacle lenses you just studied (to fix short sight and long sight), and how refraction makes the sky blue, the sunset red, and splits white light into a rainbow through a prism.

Frequently Asked Questions

Why does a pencil look bent when half of it is in water?

Light travels slower in water than in air. When the light coming from the underwater part of the pencil crosses from water into air, it changes speed and bends away from its original path. Your eyes trace that bent ray back in a straight line, so the underwater part looks shifted — making the whole pencil seem broken or bent at the water surface. This bending of light when it passes from one medium to another is called refraction.

What is the difference between a concave and a convex mirror?

A concave mirror curves inwards (like the inside of a spoon) and converges parallel light rays to a real focus in front of it, so it can form both real and virtual images and is used in torches, shaving mirrors and headlights. A convex mirror curves outwards (like the back of a spoon), spreads light rays apart, and always forms a small, upright, virtual image — which is why it is used as a vehicle rear-view mirror to give a wide field of view.

What does a negative sign in magnification mean?

Magnification m is negative when the image is real and inverted, and positive when the image is virtual and erect. The size of the number tells you how big the image is compared with the object: if the magnitude is more than 1 the image is enlarged, if it is less than 1 the image is smaller, and if it is exactly 1 the image is the same size. So m = -2 means a real, inverted image that is twice the object's size.

Why is the focal length of a concave mirror taken as negative?

By the New Cartesian sign convention, all distances are measured from the pole of the mirror, and any distance measured against the direction of the incoming light (to the left) is negative. For a concave mirror the focus lies in front of the mirror, on the same side as the object, so its focal length is measured to the left and comes out negative. For a convex mirror the focus is behind the mirror, so its focal length is positive.

What is the power of a lens and what is a dioptre?

The power of a lens tells you how strongly it bends light. It is the reciprocal of the focal length in metres: P = 1/f. Its unit is the dioptre (D), so a lens of focal length 1 metre has a power of 1 D. A convex (converging) lens has positive power and a concave (diverging) lens has negative power. A shorter focal length means a more strongly bending lens and a larger power.