Electricity
Why This Matters
Flick a switch and a room lights up. Plug in a charger and your phone slowly fills up again. Look around you. Fans, fridges, phones, trains — almost everything runs on the same invisible thing flowing through wires. But what is really flowing inside those wires? And here is a puzzle: a heater coil glows red-hot, but the wire bringing power to it stays cool. Why?
This chapter answers all of that. You will learn what electric current really is. You will learn what pushes it along (voltage). You will learn what slows it down (resistance). And you will learn one simple rule, called Ohm’s law, that links all three together. Once you know this rule, you can work out what any simple circuit will do.
This is not just theory. Why does a fuse “blow”? Why are the appliances in your house wired in parallel and not in series? Why is your electricity bill measured in “units”? By the end of this chapter, all of these will make complete sense.
The Big Idea
Current is the flow of electric charge. A potential difference (also called voltage) is the push that drives that charge through a wire. Resistance is whatever slows the charge down. Ohm’s law links all three: V = IR. Push harder (more V) and you get more current. Slow it down more (more R) and you get less current.
The easiest way to picture this is water flowing in a pipe. The voltage is like the water pressure that makes the water flow. The current is how much water flows past a point each second. The resistance is how narrow or blocked the pipe is. A narrow, clogged pipe lets less water through. That is the whole chapter in one picture. The rest is just this idea made exact, and then used for groups of resistors, heating, and power.
Let’s Break It Down
Electric current
Before we talk about current, let’s quickly refresh what charge and electrons actually are — because that is the stuff doing the flowing.
First, what is charge? Charge is a basic property of tiny particles. Electrons carry charge, and that is what moves through wires. When this electric charge flows through a conductor (a material that lets charge pass through it easily, like a metal wire), we say there is an electric current in it. So current means charge is flowing.
Current is the rate of flow of charge. In simple words, it tells you how much charge passes a point in the wire each second. More charge per second means more current.
Suppose a charge Q flows past one spot in the wire in a time t. Then the current I is:
I = Q / t
Now the units. The SI unit of charge is the coulomb (C). One coulomb is the charge of about 6 × 10¹⁸ electrons. (Each single electron carries a very tiny charge of 1.6 × 10⁻¹⁹ C, so you need a huge number of them to make one coulomb.) The SI unit of current is the ampere (A). One ampere means one coulomb of charge flows past a point every second (1 A = 1 C/s). Currents in small devices are often much smaller, so we use milliamperes (1 mA = 10⁻³ A, one-thousandth of an ampere) or microamperes (1 µA = 10⁻⁶ A, one-millionth of an ampere).
To measure current we use an ammeter. An ammeter is always connected in series in the circuit. “In series” means it is placed in the same line as the wire, so all the current passes straight through it.
Here is one thing that surprises many students. Inside a metal wire, the particles that actually move are the electrons, and electrons carry negative charge. But when scientists first studied current, electrons had not been discovered yet. So they fixed a rule: the direction of current is the direction in which positive charge would move. This means the current direction is taken as opposite to the way the electrons really flow. So we say current flows from the + terminal of the cell, through the circuit, to the − terminal.
Let’s put I = Q/t to work. Here’s a quick one: if we know the current and how long it flows, can we find the total charge?
A bulb filament draws 0.5 A for 10 minutes. How much charge flows through it?
- First, change everything into SI units. The current is already I = 0.5 A. The time is t = 10 min. Since 1 minute = 60 seconds, t = 10 × 60 = 600 s.
- We know I = Q/t. We want the charge Q, so we rearrange this to Q = I × t.
- Now put the numbers in: Q = 0.5 A × 600 s = 300 C.
Potential difference (voltage)
Charge will not flow on its own. Think of water in a pipe lying flat on the ground. The water just sits there, because there is nothing to push it. To make charge flow, you need a “push.” This push is a difference in electric pressure between two points, and we call it the potential difference (or voltage). A cell or a battery creates this push using chemical energy. The push is there even before any current starts to flow.
We keep mentioning the cell and the circuit, so let’s pin down exactly what each one is before going further.
So what exactly is potential difference? The potential difference V between two points is the work done (W) to move one unit of charge (Q) from one point to the other. Work just means the energy spent to move the charge. In short, voltage tells you how much energy each bit of charge carries.
V = W / Q
The SI unit is the volt (V). One volt is the potential difference when 1 joule of work is needed to move 1 coulomb of charge:
1 V = 1 J/C
To measure potential difference we use a voltmeter. A voltmeter is always connected in parallel. “In parallel” means it is connected across the two points whose voltage you want to measure, on a side branch, not in the main line.
Let’s see V = W/Q in action — this time finding the energy (work) needed to push a charge across a known voltage.
How much work moves a charge of 2 C across a potential difference of 12 V?
- Write down what is given: Q = 2 C, V = 12 V.
- We know V = W/Q. We want the work W, so rearrange it to W = V × Q.
- Put the numbers in: W = 12 V × 2 C = 24 J.
Circuit diagrams
Drawing every battery and bulb as a real picture takes too long. So instead we use simple standard symbols that everyone agrees on. A closed, unbroken path for the current to flow around is called an electric circuit. If you break this path anywhere, the current stops at once. This is exactly what a switch does.
Figure 11.1 below shows what a real circuit looks like once we replace the picture of every part with its symbol.
Here are the most common symbols. A cell is shown as one long line (the + terminal) and one short line (the − terminal). A battery is just several cells joined together. A switch (also called a plug key) can be drawn open or closed. A resistor is drawn as a zig-zag or a rectangle. A rheostat is a resistor whose value you can change. An ammeter is a circle with the letter A inside it, and a voltmeter is a circle with the letter V inside it.
Ohm’s law
This is the most important rule in the chapter. In 1827, a scientist named Georg Simon Ohm did experiments on metal wires. He found that the potential difference V across a metal conductor is directly proportional to the current I flowing through it. “Directly proportional” means that if you double V, then I also doubles. This is true as long as the temperature of the wire stays the same.
V ∝ I, so V = IR
The constant R in this equation is the resistance of the conductor. Resistance is how strongly the conductor opposes the flow of charge. A high resistance fights the current hard. Its SI unit is the ohm, written with the symbol Ω.
We can rearrange V = IR in two useful ways:
R = V / I and I = V / R
If 1 volt pushes a current of 1 ampere through something, then its resistance is 1 Ω. Look carefully at the last form, I = V / R. For a fixed voltage, more resistance means less current. For example, if you double the resistance, the current drops to half. A device that you can adjust to change the resistance, and so control the current, is called a rheostat.
If you draw a graph of V (on the up-and-down y-axis) against I (on the across x-axis) for such a conductor, you get a straight line passing through the origin (the point 0,0). That straight line is Ohm’s law shown as a picture. The steepness (slope) of the line is equal to the resistance R. Figure 11.2 below shows this graph.
Time to use I = V/R. Let’s see how the same 220 V supply gives very different currents to a high-resistance bulb and a low-resistance heater.
A 220 V source connects to (a) a bulb of resistance 1200 Ω, (b) a heater coil of 100 Ω. Find each current.
- The voltage is given and we want the current, so use I = V/R.
- For the bulb, R = 1200 Ω: I = 220 V / 1200 Ω = 0.18 A.
- For the heater, R = 100 Ω: I = 220 V / 100 Ω = 2.2 A. The heater has much lower resistance, so it pulls a much bigger current from the same supply. That big current is why it heats up.
What resistance depends on
So what makes one wire resist current more than another? To answer that, we first need to know where resistance even comes from. Picture the inside of the wire: the metal atoms sit fixed in place, and the free electrons drift through the gaps between them. Figure 11.3 below zooms inside the wire to show this.
So resistance is really just electrons bumping into atoms. Every bump slows an electron down and steals a little of its energy. Now the three factors make perfect sense:
- It is directly proportional to the length (l). A longer wire has more resistance. (Charge has to push through more wire.)
- It is inversely proportional to the area of cross-section (A). The cross-section is how thick the wire is when you cut across it. A thicker wire has less resistance. (Charge has more room to flow.)
- It depends on the material the wire is made of. Copper and rubber behave very differently.
We can put all three together in one formula:
R = ρ × (l / A)
Here ρ (the Greek letter rho) is the resistivity of the material. Resistivity is a number that belongs to the material itself, no matter what shape it is in. It tells you how good or bad that material is at carrying current. It is measured in Ω m (ohm metre). Good conductors like silver and copper have very low resistivity (about 10⁻⁸ Ω m), so current flows easily. Insulators like glass and rubber have huge resistivity (10¹² Ω m or even more), so current can barely get through. That is exactly why wires are made of copper and their covering is made of rubber.
Figure 11.4 below sums up all three factors side by side, so you can see at a glance how length, thickness and material each pull resistance up or down.
Here are a few useful facts. An alloy is a mixture of metals. Alloys like nichrome have higher resistivity than pure metals. They also do not get spoiled (oxidise) easily when they get hot. Both of these make alloys perfect for the heating parts inside toasters and irons. Tungsten is used for the thin wire (filament) inside bulbs because it has a very high melting point, so it can glow white-hot without melting. Copper and aluminium are used in the long power lines that carry electricity to your home, because their low resistivity wastes very little energy on the way.
Let’s test how well you can read R = ρl/A: what happens to the resistance if we halve the length and double the thickness of the same wire?
A wire has resistance 4 Ω. What is the resistance of another wire of the same material with half the length (l/2) and double the area (2A)?
- Start from the formula R = ρl/A. The material is the same, so ρ does not change.
- For the new wire, the length is l/2 and the area is 2A. Put these in: R₂ = ρ(l/2)/(2A). Pulling the numbers out, this is (1/2) ÷ 2 = 1/4 times the old value, so R₂ = (1/4) × ρl/A.
- For the first wire, ρl/A = 4 Ω. So R₂ = (1/4) × 4 Ω = 1 Ω. Making the wire shorter and thicker both lower the resistance.
Resistors in series
When resistors are joined end to end, one after another in a single line, we say they are in series. In a series connection, the same current flows through every resistor (there is only one path, so the current has nowhere else to go). The voltages across the separate resistors add up to give the total voltage. The combined resistance (called the equivalent resistance) is simply the sum of all of them:
But why is the current the same everywhere while the voltage gets shared out? Think of the water-pipe picture again. Figure 11.5 below imagines one single loop of pipe with a pump and two waterwheels, one after the other, with no branches anywhere.
Here is the key. Because there is only one pipe and no junction, every drop of water that leaves the pump must pass through both wheels and come back. Nothing can pile up or escape on the way. So the amount of water flowing past every point each second is the same — that is why the current is identical through each resistor. The push (voltage) is different, though. Each wheel “uses up” some of the pump’s pressure to turn. So the pump’s total push is shared between the wheels, which is why the voltages add up: V = V₁ + V₂.
The same idea as a real circuit diagram is shown in Figure 11.6 below.
Rₛ = R₁ + R₂ + R₃
The total resistance in series is always larger than any single resistor in the line. There is one big drawback. Since there is only one path, if even one part fails, the whole circuit breaks and everything stops. You may have seen this with old string lights for Diwali: if one bulb fuses, the whole string goes dark.
Let’s put the series rules together in one go — finding the total resistance, the single current, and how the voltage splits between two parts.
A 20 Ω lamp and a 4 Ω conductor are in series across a 6 V battery. Find the total resistance, the current, and the voltage across each.
- They are in series, so add the resistances: total R = 20 + 4 = 24 Ω.
- The current is the same everywhere in a series circuit. Find it with I = V/R = 6 V / 24 Ω = 0.25 A.
- Now find the voltage across each part using V = IR. Across the lamp: 20 Ω × 0.25 A = 5 V. Across the conductor: 4 Ω × 0.25 A = 1 V. Quick check: 5 V + 1 V = 6 V, which matches the battery ✓.
Resistors in parallel
When resistors are joined side by side between the same two points, we say they are in parallel. Now each resistor is its own separate branch. The voltage across each branch is the same, because they all connect to the same two points. The current splits up among the branches, and the separate currents add up to the total. The equivalent resistance is found using a “reciprocal” rule, which means we add up 1 divided by each resistance:
This is the opposite of series, so let’s see why with the same water picture. In Figure 11.7 below the pipe splits at a junction into two separate branches, each with its own wheel, and the branches join up again.
Here is the reason. Both branches begin at the same point X and end at the same point Y. The difference in “pressure” between X and Y is a single, fixed amount. So every branch stretched between X and Y feels exactly that same push — that is why the voltage is the same across each branch. But the water now has a choice of paths, so it splits up between them. The flows in the branches then add back together, which is why the currents add: I = I₁ + I₂.
The same idea as a real circuit diagram is shown in Figure 11.8 below.
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
The total resistance in parallel is always smaller than the smallest single resistor. This sounds strange at first, so Figure 11.9 below pictures a crowd of people trying to get through a wall with just one doorway versus the same wall with two doorways.
The reason it feels strange is that in everyday life “adding more” usually means “more total.” But adding a parallel branch is like opening another door: it never closes the door you already had. It only gives the current an extra way through. With more ways through, the same push moves more current, and “more current for the same push” is exactly what lower resistance means. That is also why we add the 1/R values, not the R values — each branch adds to how easily current flows, and easiness is 1/R. This is exactly why the appliances in your home are wired in parallel. Each one gets the full 220 V it needs. Each can be switched on or off on its own. And if one stops working, the rest keep running.
Now let’s work a full parallel example: three different resistors across one battery, finding each branch current and proving the total resistance really does come out smaller than the smallest branch.
R₁ = 5 Ω, R₂ = 10 Ω, R₃ = 30 Ω are connected across a 12 V battery. Find the current in each, the total current, and the total resistance.
- This is a parallel circuit, so each resistor has the full 12 V across it. Find the current in each branch with I = V/R.
- I₁ = 12/5 = 2.4 A. I₂ = 12/10 = 1.2 A. I₃ = 12/30 = 0.4 A. The total current is the sum of the branch currents: I = 2.4 + 1.2 + 0.4 = 4 A.
- Now the total resistance: 1/Rₚ = 1/5 + 1/10 + 1/30. To add these, make the bottom numbers the same (30): 6/30 + 3/30 + 1/30 = 10/30 = 1/3. So Rₚ = 3 Ω. Notice it is smaller than every branch. Quick check: 12 V / 3 Ω = 4 A, which matches the total current ✓.
Heating effect and electric power
To keep the current flowing, the source (cell or battery) has to keep spending energy. In a circuit that has only resistance, all of this energy turns into heat. This is called the heating effect of current. The amount of heat produced is given by:
H = VIt = I²Rt
This is known as Joule’s law of heating. It tells us that the heat depends on three things: the square of the current (I²), the resistance (R), and the time (t). The “square of the current” part is important. It means that even a small rise in current produces a lot more heat.
But why does pushing current through a wire make it hot at all — and why does double the current give so much more heat? It comes straight from those electron-atom bumps we just met. Figure 11.10 below shows what is happening.
So the heat is simply all those collisions adding up. Each bump turns a little of the electron’s push-energy into the jiggling of the atoms, and jiggling atoms is heat. Now, why I² and not just I? Doubling the current means roughly twice as many electrons, each also moving faster. So you get more bumps and harder bumps — the two effects multiply together, and the heat shoots up about four times. This heating effect is what makes heaters, irons, toasters and bulbs work. It is also the idea behind the fuse. A fuse is a thin piece of wire that melts and breaks the circuit if the current becomes too large and dangerous, protecting your devices.
We often want to know how fast energy is being used, not just the total. The rate at which energy is used is called electric power:
P = VI = I²R = V²/R
The SI unit of power is the watt (W). One watt means one joule of energy used per second (1 W = 1 V × 1 A). To get the total energy, use Energy = power × time. For your electricity bill, joules are too small to be handy, so power companies use a bigger unit called the kilowatt-hour (kW h). This is the “unit” you see on the bill:
1 kW h = 3.6 × 10⁶ J
So how does all this turn into the rupees on your electricity bill? Let’s actually cost out a fridge running every day for a month.
A 400 W fridge runs 8 hours a day for 30 days, at ₹3.00 per kW h. Find the cost.
- We want the cost, so first we need the total energy used, in kW h.
- Energy = power × total time. The fridge runs 8 hours a day for 30 days, so total time = 8 × 30 = 240 hours. Energy = 400 W × 240 h = 96000 W h. Since 1 kW h = 1000 W h, this is 96000 ÷ 1000 = 96 kW h.
- Now multiply by the rate: Cost = 96 kW h × ₹3.00 = ₹288.00.
Common Mistakes
Current flows from the − terminal to the + terminal, because electrons move that way.
The electrons, which are the particles that really move, do flow from − to +. So it feels natural to say current goes the same way as the real particles.
There is a fixed rule that everyone follows: current is defined in the opposite direction to the electrons. So current flows from the + terminal, through the circuit, to the − terminal.
An ammeter goes in parallel and a voltmeter in series.
Both meters look similar and connect with two wires, so it is easy to mix up which goes where.
It is the other way round. The ammeter goes in SERIES, so all the current passes through it. The voltmeter goes in PARALLEL, across the two points you are measuring. Connecting them the wrong way can damage the meter.
Adding more resistors always increases the total resistance.
In everyday life, adding more of something gives you more of it. The series case, which you learn first, agrees with this idea.
This is true only in series, where the resistances add up. In parallel, each new resistor gives the current another path to flow through. So the total resistance actually goes DOWN, and it ends up smaller than the smallest branch.
A thicker wire has more resistance because there is more metal in it.
More metal sounds like more stuff to push through. It is also easy to confuse thickness with length, and a longer wire really does add resistance.
Resistance is inversely proportional to area. So a thicker wire (bigger area) has LESS resistance, because the charge has more room to flow. Length works the opposite way: a longer wire has more resistance.
Quick Check
What is the SI unit of electric charge, and roughly how many electrons make it up?
A conductor obeys Ohm's law. If you double the potential difference across it (temperature unchanged), the current through it will:
Three 6 Ω resistors are connected in parallel. What is their equivalent resistance?
Why are heating elements (in toasters and irons) made of an alloy like nichrome rather than a pure metal?
Your home appliances are all connected in parallel across 220 V. Give two reasons why parallel is better than series for this.
Two reasons: (1) Each appliance gets the full 220 V it is built to run on. In series, the 220 V would get shared out among them, so each would get less. (2) Each one can be switched on or off on its own, and if one fails the others keep working. In series, one broken part stops the whole circuit. (A bonus reason: parallel gives a lower total resistance, which lets through the larger total current that many appliances together need.)
Practice Problems
A current of 0.5 A flows for 4 minutes. How much charge passes through the circuit?
First change the time to seconds: t = 4 min = 4 × 60 = 240 s. Then use Q = I × t = 0.5 A × 240 s = 120 C.
When a 12 V battery is connected across an unknown resistor, a current of 2.5 mA flows. Find the resistance.
First change the current to amperes: I = 2.5 mA = 2.5 × 10⁻³ A = 0.0025 A. Then use R = V/I = 12 V / 0.0025 A = 4800 Ω (4.8 kΩ).
A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω. How much current flows through the 12 Ω resistor?
In a series circuit the same current flows through every resistor. So we just find the total resistance and use Ohm’s law. Add all the resistances: Total R = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 Ω. Now find the current: I = V/R = 9 V / 13.4 Ω ≈ 0.67 A. This is the current through the 12 Ω resistor, and through every other resistor as well.
How can three resistors, each of 6 Ω, be connected to give a total resistance of (i) 9 Ω, (ii) 4 Ω?
(i) 9 Ω: First put two of the 6 Ω resistors in parallel. Then put that pair in series with the third 6 Ω resistor. The parallel pair: 1/R = 1/6 + 1/6 = 2/6, so R = 3 Ω. Now in series with the last 6 Ω: 3 + 6 = 9 Ω ✓.
(ii) 4 Ω: First put two of the 6 Ω resistors in series, which gives 6 + 6 = 12 Ω. Then put that 12 Ω in parallel with the third 6 Ω. 1/R = 1/12 + 1/6. Make the bottoms the same: 1/12 + 2/12 = 3/12, so R = 4 Ω ✓.
An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.
Use Joule’s law: H = I²Rt. Here I = 5 A, R = 20 Ω, t = 30 s. H = (5)² × 20 × 30 = 25 × 20 × 30 = 25 × 600 = 15000 J (which is 15 kJ).
Two lamps, one rated 100 W and the other 60 W, both at 220 V, are connected in parallel to a 220 V supply. What total current is drawn from the line?
Because they are in parallel, each lamp gets the full 220 V. Find each current from P = VI, rearranged to I = P/V. Lamp 1: I₁ = 100 W / 220 V ≈ 0.45 A. Lamp 2: I₂ = 60 W / 220 V ≈ 0.27 A. In parallel the branch currents add up: I = I₁ + I₂ ≈ 0.45 + 0.27 = 0.73 A. (You can also do it in one step: total power = 100 + 60 = 160 W, so I = 160/220 ≈ 0.73 A.)
A hot plate connected to 220 V has two coils A and B, each 24 Ω, which can be used separately, in series, or in parallel. Find the current in all three cases.
For each arrangement, first find the resistance, then use I = V/R. One coil alone (24 Ω): I = 220 / 24 ≈ 9.2 A. Both in series (24 + 24 = 48 Ω): I = 220 / 48 ≈ 4.6 A. This is the lowest current, so it gives the least heat. Both in parallel: 1/R = 1/24 + 1/24 = 2/24, so R = 12 Ω. I = 220 / 12 ≈ 18.3 A. This is the highest current, so it gives the most heat. So one hot plate can give three different heat settings, just by changing how the two coils are connected.
Summary
- Current I = Q/t is how fast charge flows. Its SI unit is the ampere (A). Current flows opposite to the electrons. It is measured by an ammeter, connected in series.
- Potential difference V = W/Q is the push that drives the current. Its SI unit is the volt (V) (1 V = 1 J/C). It is measured by a voltmeter, connected in parallel.
- Ohm’s law: V = IR. Resistance R (in ohms, Ω) opposes the current. The V–I graph is a straight line through the origin.
- Resistance R = ρl/A. It is directly proportional to length, inversely proportional to area, and depends on the material through its resistivity ρ.
- Series: same current through all; Rₛ = R₁ + R₂ + R₃ (bigger than any one). Parallel: same voltage across all; 1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃ (smaller than the smallest).
- Heating effect: H = I²Rt (Joule’s law). Used in heaters and bulbs, and in the safety fuse.
- Electric power: P = VI = I²R = V²/R, measured in watts. Energy is sold in kilowatt-hours (1 kW h = 3.6 × 10⁶ J).
What’s Next
You now know how current flows, and how resistance and voltage control it. But electricity has one more amazing trick. A wire that carries current makes a magnetic field around it. And the opposite is also true: a moving magnet can create a current in a wire. This two-way link between electricity and magnetism is what makes every electric motor spin. It is also how almost all the electricity you use is generated.
In Chapter 12: Magnetic Effects of Electric Current, you will learn about magnetic field lines, the field around a wire and around a coil, how a motor spins, how a moving magnet makes current (electromagnetic induction), and how a generator turns motion into electricity.
Frequently Asked Questions
What is the difference between AC and DC current?
DC (direct current) flows in only one direction — like the current from a battery. AC (alternating current) keeps reversing direction many times a second — this is what comes from the wall socket in your home (in India at 50 Hz, meaning it reverses 50 times every second). AC is used for power distribution because it can be stepped up to very high voltages for long-distance transmission and then stepped back down, which DC cannot do as easily.
Why do resistors connected in parallel have a lower total resistance than any single resistor?
Think of each resistor as a separate path the current can take. Adding more paths gives the charge more routes to flow through at the same time, so more current flows for the same voltage — which means the overall resistance is lower. The formula 1/Rₚ = 1/R₁ + 1/R₂ + ... captures this: adding another term always makes the right-hand side bigger, which means Rₚ gets smaller.
Why does a heater wire glow red-hot but the connecting wire stays cool?
The heating effect of current depends on resistance — the formula is H = I²Rt. The heater element is made of nichrome, a material with very high resistance. The connecting copper wire has very low resistance. The same current flows through both, but the heater wire converts far more electrical energy into heat because of its high resistance, while the copper wire barely heats up at all.
What is Ohm's law and when does it apply?
Ohm's law states that the current through a conductor is directly proportional to the potential difference across it, provided the temperature stays constant — written as V = IR. It applies to metallic conductors (like copper and nichrome wires) kept at a constant temperature. It does NOT apply to devices like a diode or a bulb filament that heats up and changes resistance as current flows.
What is a kilowatt-hour and how is the electricity bill calculated?
A kilowatt-hour (kWh), also called one 'unit', is the energy used by a 1 kW device running for 1 hour. Your electricity bill counts how many units your home uses. To find the energy an appliance uses: multiply its power in kilowatts by the number of hours it runs. For example, a 100 W (0.1 kW) bulb running for 10 hours uses 0.1 × 10 = 1 kWh, which is 1 unit.