Tales by Dots and Lines
Why This Matters
Open any newspaper. You will see numbers everywhere. The average rainfall this year. The middle income of a town. A graph of cricket scores match by match. A chart of who likes which subject in a class.
These are not just numbers. They are stories. A line that climbs tells the story of something growing. A short bar next to a tall one tells you one thing is far less common than another. A single dot sitting far away from the rest tells you something unusual happened.
But here is the catch. The same data can be told in honest ways and misleading ways. A shop owner could say “our customers spend ₹500 on average” — and that could be true even if almost everyone spends ₹100 and one rich customer spent ₹5000. The “average” hid the real story.
This chapter teaches you to read these stories carefully and tell them clearly. You will understand what an average really means (it is a balance point, not just a sum-divided-by-count). You will learn when the average lies and the median tells the truth. And you will learn to draw and read the pictures — dot plots, bar graphs and line graphs — that turn a pile of numbers into something you can see in one glance.
The Big Idea
The mean (average) of data is a balance point: it sits at the spot where the total distance to the values on its left exactly equals the total distance to the values on its right. The median is simply the middle value when the data is lined up in order. The mean uses every value, so one far-away value (an outlier) can drag it; the median only watches the middle, so it stays steady. To see data instead of just listing it, we draw dot plots (a dot for each value), bar graphs (bar height shows a count) and line graphs (a line shows how something changes over time).
Let’s Break It Down
Last year you met the mean and the median. We will not just repeat them. We will look at them in a fresh way and learn why they behave the way they do. Let us first jog your memory.
The mean is a balance point
Take just two numbers, say 3 and 7. Their mean is (3 + 7) ÷ 2 = 5. Notice something: 5 is exactly halfway between 3 and 7. It is 2 away from 3 on the left and 2 away from 7 on the right. The two distances are equal.
This is the real secret of the mean. The mean is the point where the data “balances”. Imagine the values as little weights placed along a ruler, and imagine the ruler resting on a single support, like a see-saw. The mean is exactly where you must put the support so the see-saw does not tip either way.
But be careful. People sometimes think the mean is just the middle of the smallest and largest value. It is not. What is really equal is the total distance on each side. Let us see this with the data 10, 10, 11, 17, whose mean is 12. Figure 5.1 below shows the see-saw.
Let us check that arithmetic, because it is the whole point. To the left of 12: the value 10 is 2 away, the second 10 is also 2 away, and 11 is 1 away. Add those distances: 2 + 2 + 1 = 5. To the right of 12: only 17, which is 17 − 12 = 5 away. Both sides total 5. They balance.
Total distance to the values on the left = total distance to the values on the right.
This also explains why there is only one mean. Suppose you tried a centre bigger than 12, say 13. Then every left value is now further away (their distances all grow) and the right value 17 is now closer (its distance shrinks). The two sides no longer match — 13 is not a balance point. The same goes for any value below 12. So 12 is the only place that balances, which is why every data set has exactly one mean.
The mean of some data is 20. One value in the data is 26. How far is that value from the mean, and is it on the left or right of the balance point?
The value 26 is 26 − 20 = 6 away from the mean. Since 26 is bigger than 20, it sits to the right of the balance point. To stay balanced, the values on the left must add up to a total distance of 6 as well.
What happens to the mean when data changes?
Because the mean is a balance point, we can predict how it moves without redoing the whole sum. This saves a lot of work.
Adding a value bigger than the mean pushes the mean up. Think of the see-saw. If you drop a new weight far out on the right, the right side gets heavier, so the balance point must shift right to even things out. So the mean increases. In the same way, adding a value smaller than the mean pulls the mean down.
Adding a value exactly equal to the mean changes nothing. A weight placed right on the support does not tip the see-saw at all. So the mean stays the same.
Add the same number to every value, and the mean shifts by that same number. If every score goes up by 10, the whole picture slides 10 to the right — so its balance point slides 10 to the right too. Let us prove this neatly with algebra.
The mean of some data is a. Now we add the number 3 to every single value. Show that the new mean is a + 3.
- Say there are n values, written x₁, x₂, x₃, … xₙ. Their mean is a, which means (x₁ + x₂ + … + xₙ) ÷ n = a.
- Now add 3 to every value. The new values are (x₁ + 3), (x₂ + 3), … (xₙ + 3). The new mean is their sum divided by n.
- The new sum = (x₁ + x₂ + … + xₙ) + (3 added n times) = (old sum) + 3n. So the new mean = (old sum + 3n) ÷ n.
- Split the fraction: (old sum ÷ n) + (3n ÷ n) = a + 3. So the new mean is a + 3 — exactly 3 more than before, just as the see-saw picture suggested.
Double every value, and the mean doubles. If you stretch every weight’s position to twice its distance from zero, the whole arrangement stretches out, and so does the balance point. By the same algebra (multiply each value by 5, factor the 5 out of the sum), multiplying every value by a number multiplies the mean by that number too.
This idea is genuinely useful. Here is a classic example.
Shreyas measured the heights of 24 students and got an average of 150.2 cm. Then the teacher noticed every student was wearing shoes that add 1 cm to their height. What is the correct average height (without shoes)? Do we need to measure everyone again?
- Every measured height is 1 cm too big, because the shoes added exactly 1 cm to each student.
- So the real data is “every value reduced by 1”. From our rule, subtracting the same number from every value subtracts that same number from the mean.
- No need to measure anyone again! Just subtract 1 from the average: 150.2 − 1 = 149.2 cm. That is the correct average height.
Finding a missing value using the mean
The mean links the sum and the count. If you know the mean and the count, you know the sum. That lets you fish out a missing value.
Coach Balwan wrote down the weights of 10 wrestlers: 42, 40, 39, 33, 48, 38, 42, 35, 32, and one more that got smudged. The mean weight is 39.2 kg. Find the smudged weight w.
- Mean = (sum of all 10 weights) ÷ 10. So the sum of all 10 weights = mean × 10 = 39.2 × 10 = 392.
- Add the nine weights we can read: 42 + 40 + 39 + 33 + 48 + 38 + 42 + 35 + 32 = 349.
- So 349 + w = 392. That gives w = 392 − 349.
- w = 43. The smudged weight is 43 kg.
When the median beats the mean: outliers
Here is where the mean can mislead. An outlier is a value that sits far away from all the others — a giant or a tiny one.
Because the mean uses every value in its sum, a single outlier can drag it a long way. The median, on the other hand, only watches the middle position. It does not care how far out the extreme value is. So an outlier usually pulls the mean but leaves the median calm.
Let us see it with five test marks: 18, 19, 20, 21, 22. Both the mean and median are 20. Now imagine the last mark was actually 90 (maybe a typing error, or one student who did spectacularly). Figure 5.2 below compares the two cases.
Check the mean in case (b): (18 + 19 + 20 + 21 + 90) ÷ 5 = 168 ÷ 5 = 33.6. That “average” of 33.6 is higher than four of the five marks! It does not describe a typical student at all. The median, 20, still does. This is why, for things like incomes or house prices where a few huge values exist, people often report the median — it is not fooled by the giants.
The median follows its own version of the “include a value” rule too. If you add a value bigger than the current median, the middle shifts up a little, so the median rises (or stays). Add a value smaller than the median, and it falls (or stays). But it shifts gently, by position — never leaping the way the mean can.
A small company has salaries (in thousands) of 20, 22, 24, 25, and the owner takes 500. Would the mean or the median better describe a typical worker's salary?
The median is better here. The owner’s 500 is a huge outlier that drags the mean far above what any worker earns. The median ignores how extreme that value is and stays near the middle of the workers’ salaries, around 23–24 thousand, which is much closer to typical.
Organising data with frequencies
When the same value appears many times, writing it out again and again is wasteful. Instead we make a frequency table: one row of values, one row saying how many times (the frequency) each value occurs.
Say we collect the family size of 36 students. The table might look like this:
| Family size | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|---|---|---|---|---|---|---|---|---|
| Frequency (no. of students) | 3 | 11 | 9 | 7 | 3 | 1 | 1 | 1 |
A tempting mistake is to do (3 + 4 + 5 + 6 + 7 + 8 + 9 + 10) ÷ 8. But that pretends each value happened once! The number 4 happened eleven times — it should count eleven times. To find the mean, multiply each value by its frequency, add those up, and divide by the total count.
Using the family-size table above (36 students in all), find the mean and the median family size.
- For the mean, multiply each value by its frequency and add: (3×3) + (4×11) + (5×9) + (6×7) + (7×3) + (8×1) + (9×1) + (10×1) = 9 + 44 + 45 + 42 + 21 + 8 + 9 + 10 = 188.
- Total number of students = 3 + 11 + 9 + 7 + 3 + 1 + 1 + 1 = 36. So mean = 188 ÷ 36 ≈ 5.22.
- For the median of 36 values, the middle is between the 18th and 19th values in sorted order. We add frequencies from the smallest value until we pass 18 and 19.
- Up to value 4: 3 + 11 = 14 students (positions 1–14). Up to value 5: 14 + 9 = 23 students (positions 15–23). So positions 18 and 19 both land on the value 5. The median family size is 5.
Notice the trick in Step 4: we did not write out all 36 numbers. By adding up frequencies, we found which value sits in the middle positions quickly. This is the everyday way to read a median off a frequency table.
Visualising data: dot plots
Numbers in a list are hard to feel. A picture makes the shape of the data jump out. The simplest picture is a dot plot: draw a number line, and put one dot above a value for each time it occurs. A tall stack means that value is common.
Here is the same family-size data as a dot plot (using a smaller class so it is easy to see). Figure 5.3 shows it.
A dot plot is great for small data. You can instantly spot the most common value (the tallest stack), any gaps, and any lonely dot far from the rest (an outlier). And because you can see each value’s distance from the centre, a dot plot is the natural way to picture the balance-point idea.
Visualising data: bar graphs
When you are comparing separate groups — not a number line, but categories like fruits or subjects — a bar graph is the right picture. Each group gets a bar, and the bar’s height shows its count. Taller bar, bigger count.
The most important rule: the heights must be drawn to scale. If 12 is the value, the bar must reach the 12 mark on the vertical axis — not “a bit taller than the others”. Figure 5.4 shows a bar graph of favourite fruits, drawn carefully to scale.
To read a bar graph, look across from the top of a bar to the vertical scale. To draw one: choose a scale that fits your biggest value, mark the axis evenly, then draw each bar up to its value. Keep all bars the same width and leave equal gaps.
Visualising data: line graphs
Now the most powerful picture for one special job: showing how something changes over time. For that, we use a line graph. We mark each value as a point, then join the points in time order with straight line segments. The line itself tells the story — climbing, falling, flat.
Figure 5.5 below shows the monthly maximum temperature of two states across a year.
Read a line graph in two steps. Step 1 — identify what is given: what do the axes measure, what scale is used, which line is which (here, circles vs squares and a legend tell you). Step 2 — infer and interpret: read the trend. In Figure 5.5, Punjab’s temperature varies a lot (steep rise to June, steep fall after), while Kerala’s is almost constant. The steeper a segment, the faster the change.
Why a line graph and not 24 separate bars? Because the line connects the points, your eye follows the trend smoothly. A clustered bar graph of 12 months × 2 states would be 24 bars crowded together — hard to read the pattern. Line graphs are made for change over time.
You want to show how the price of petrol changed each month over the last year. Which graph fits best — a bar graph or a line graph?
A line graph. The data is one quantity (price) measured over time (each month). The connected line shows the trend — going up, down, or steady — clearly. A bar graph is better for comparing separate categories, not for following a change across time.
Common Mistakes
These slips trip up students every year. Read them once and you will dodge them.
The mean is just the middle of the smallest and largest value (smallest plus largest, divided by 2).
For two numbers, the mean really is exactly halfway between them, so students over-generalise that nice rule to all data sets.
With three or more values, the mean is the balance point, where the total distance to the values on each side is equal — not the midpoint of the extremes. For 10, 10, 11, 17 the midpoint of 10 and 17 is 13.5, but the actual mean is 12. You must add ALL the values and divide by how many there are.
To find the mean from a frequency table, just add up the different values and divide by how many different values there are.
The frequency table lists each value only once, so it looks like a short list of a few numbers, and students average those few numbers directly.
Each value must be counted as many times as its frequency. Multiply every value by its frequency, add those products, then divide by the TOTAL count (the sum of the frequencies), not by the number of different values. A value that occurs 11 times pulls the mean 11 times as hard as one that occurs once.
An outlier (one very big or very small value) changes the median just as much as it changes the mean.
Since an outlier clearly shifts the mean a lot, it feels like it must shake up every measure of the centre, including the median.
The mean adds every value, so a far-out value drags it hard. The median only depends on the MIDDLE position, not on how extreme a value is. So an outlier usually moves the mean a lot but leaves the median almost or completely unchanged. That is exactly why the median is safer when outliers are present.
Quick Check
Try these. Each one checks an idea from the chapter.
The mean is best described as which of these?
The mean of some data is 50. You add one new value, 80. What happens to the mean?
A data set is 12, 13, 14, 15, 200. Which measure best describes a typical value?
You want to show how a town's population changed every year from 2015 to 2024. Which graph is the best choice?
Practice Problems
Try each one yourself first. Only then tap to see the full solution.
Easy
Find the mean of 8, 10, 12, 14, 16.
Add all the values: 8 + 10 + 12 + 14 + 16 = 60. Count how many values there are: 5. Mean = sum ÷ count = 60 ÷ 5 = 12.
The mean of a set of 15 values is 134. Find the sum of the data.
Mean = sum ÷ count, so sum = mean × count. Sum = 134 × 15 = 2010. So all 15 values add up to 2010. (We do not need to know the individual values.)
Medium
The mean of 8, 13, 10, 4, 5, 20, y, 10 is 10.375. Find the value of y.
There are 8 values, and the mean is 10.375. So the sum of all 8 values = mean × count = 10.375 × 8 = 83. Add the seven known values: 8 + 13 + 10 + 4 + 5 + 20 + 10 = 70. So 70 + y = 83. y = 83 − 70 = 13.
Shreyas measured 24 students' heights and got an average of 150.2 cm, but everyone wore shoes adding 1 cm. Two new students then joined, with heights (without shoes) of 149 cm and 152 cm. (a) What is the correct average of the original 24, without shoes? (b) After the 2 join, does the average go up, down, or stay the same?
(a) Every measured height is 1 cm too big, so subtract 1 from the average: 150.2 − 1 = 149.2 cm is the correct average of the 24 students. (b) The two new heights are 149 cm and 152 cm. Their average is (149 + 152) ÷ 2 = 150.5 cm. Compare with the current average of 149.2 cm. The new students are taller on average than the class. Adding values above the mean pulls the mean up, so the average increases. (Exact new mean: total of 24 students = 149.2 × 24 = 3580.8; add 149 + 152 = 301, giving 3881.8 over 26 students = about 149.3 cm. Slightly higher, as predicted.)
The number of trials students took to hit a dart board's centre is given. No. of trials: 5, 6, 7, 8, 9, 10. No. of students: 4, 9, 12, 15, 10, 10. Find the mean number of trials (round to one decimal place).
This is a frequency table, so multiply each trial-count by its number of students. (5×4) + (6×9) + (7×12) + (8×15) + (9×10) + (10×10) = 20 + 54 + 84 + 120 + 90 + 100 = 468. Total number of students = 4 + 9 + 12 + 15 + 10 + 10 = 60. Mean = 468 ÷ 60 = 7.8 trials.
Challenge
Find the median of 8, 10, 19, 23, 26, 34, 40, 41, 41, 48, 51, 55, 70, 84, 91, 92. Then: (i) what single value could you add WITHOUT changing the median? (ii) what value could you remove without changing the median?
First sort — the list is already in order. There are 16 values (even count), so the median is the average of the 8th and 9th values. The 8th value is 41 and the 9th value is 41. Median = (41 + 41) ÷ 2 = 41. (i) Adding one value makes 17 values; the median becomes the 9th value alone. To keep the median at 41, add any value that is 41 or close enough that the 9th value is still 41. For example, adding 41 keeps the sorted middle at 41. (Adding any value ≥ 41 pushes the 9th position onto a 41; you can check that adding 41 itself certainly works.) (ii) Removing one value makes 15 values; the median becomes the 8th value alone. If we remove a value from the lower half, everything above shifts down one place — removing, say, 8 leaves the 8th value as 41 still. So removing 8 (or another low value) keeps the median 41.
The mean of the numbers 12, 47, 8, 73, 18, 35, 39, 8, 29, 25, p is unknown, but the median of these 11 numbers is 29. Which of these could p be: 10, 25, 40, 100, 29, 47, 30?
There are 11 numbers, so the median is the single middle value — the 6th value when sorted. First sort the 10 known numbers: 8, 8, 12, 18, 25, 29, 35, 39, 47, 73. Now we add p and need the 6th value (of all 11) to be 29. The five values below 29 are: 8, 8, 12, 18, 25. The values above 29 are: 35, 39, 47, 73. The value 29 itself is one number. For 29 to land in the 6th position, p must NOT push 29 out of the middle. If p is less than 29, then we have six values at or below 29 (8, 8, 12, 18, 25, p) and 29 sits 7th — median becomes 29 only if p itself is ≥ … let us just test each. Test p that keep 29 as the 6th value: any p ≥ 29 leaves the lower five (8,8,12,18,25) below, so 29 stays 6th. So 40, 100, 29, 47, 30 all work (each is ≥ 29). Test p < 29 (10 or 25): then six numbers are ≤ 25 (8,8,12,18,25 plus p), pushing 29 to the 7th position, so the median would be 25, not 29. So 10 and 25 do not work. Answer: p can be 40, 100, 29, 47, or 30.
The weights of a group were measured each month. Last month the mean was 65.3 kg and the median was 67 kg. This month, one person lost 2 kg and two people gained 1 kg each. What can we say about the change in the mean and the median?
For the mean: the total weight changed by (−2) + (+1) + (+1) = 0 kg. The total is unchanged and the number of people is unchanged, so the mean stays exactly 65.3 kg. For the median: the median is the middle value. Small changes of 1 or 2 kg to three people may or may not move the middle position, depending on where those people sat in the order. We are not told their positions, so we cannot be sure how the median changed — it might stay 67 kg or shift slightly. The information given is not enough to decide the median’s exact change.
Summary
- The mean (average) = sum of all values ÷ number of values. Deeper still, the mean is a balance point: the total distance to the values on its left equals the total distance on its right. That is why each data set has exactly one mean.
- Because the mean balances, you can predict its moves: adding a value above the mean raises it, a value below lowers it, and a value equal to it changes nothing. Add a fixed number to every value and the mean shifts by that number; double every value and the mean doubles.
- The median is the middle value of the sorted data (the average of the two middle values if the count is even). You can find it from a frequency table by adding up frequencies until you reach the middle position.
- An outlier (a far-away value) drags the mean but usually leaves the median steady, so the median often describes a typical value better when extremes are present.
- To find a mean from a frequency table, multiply each value by its frequency, add the products, and divide by the total count.
- Dot plots show each value as a dot (good for small data and spotting outliers). Bar graphs compare separate groups by bar height, drawn to scale. Line graphs join points in time order and are best for showing change over time — the steeper the line, the faster the change.
What’s Next
You can now read a pile of numbers as a story — where its centre sits, when an average can mislead, and which picture tells the tale best. That habit of asking “what is this data really saying?” is a life skill, not just an exam topic.
Next we return to the world of symbols and patterns. The next chapter is Algebra Play, where you will use letters to stand for numbers and uncover the rules that hide behind them. See you there!
Frequently Asked Questions
What is the mean of a set of numbers?
The mean, also called the average, is the sum of all the values divided by how many values there are. For example, the mean of 4, 6 and 8 is (4 + 6 + 8) divided by 3, which is 18 divided by 3, equal to 6. The mean acts like a balance point of the data.
What is the difference between mean and median?
The mean is the sum of all values divided by the number of values. The median is the middle value when the data is sorted in order. If there are two middle values, the median is the average of those two. The mean uses every value, but the median only looks at the position in the middle.
Why does the median not change when there is an outlier?
An outlier is a value far away from the rest. The mean adds up every value, so a very large or very small value drags it. The median only cares about the middle position, not how far away the extreme value is, so one outlier usually leaves the median unchanged.
What happens to the mean if every value increases by the same number?
The mean increases by that same number. If you add 10 to every value, the whole data shifts right by 10, so its balance point also shifts right by 10. In the same way, if every value is doubled, the mean doubles too.
When should I use a line graph instead of a bar graph?
Use a line graph when you want to show how a value changes over time, like temperature across months. The connected line makes the trend easy to see. A bar graph is better for comparing separate groups, like the favourite fruit of a class.