Proportional Reasoning – 2
Why This Matters
You make these decisions every single day, often without noticing.
You are cooking for two friends, but suddenly four more turn up. How much more rice and dal do you need? You are riding a bicycle to school, but today you take a bus instead. Will you reach faster, and by how much? Three people are painting a wall and it is taking too long, so two more join in. How many days will it take now?
Each of these is a question about how one quantity changes when another changes. Sometimes the two go up together — more friends, more food. Sometimes one goes up while the other goes down — more painters, fewer days.
This chapter teaches you to spot the difference, and to put exact numbers on it. Once you can, you will never again guess “how much” — you will calculate it. That single skill quietly powers cooking, shopping, travel, building, and even reading a map.
The Big Idea
Two quantities can be linked in two opposite ways. In direct proportion, they grow together by the same factor — double one and the other doubles, so their quotient (y ÷ x) stays fixed. In inverse proportion, one grows as the other shrinks by the same factor — double one and the other halves, so their product (x × y) stays fixed. The whole chapter is learning to tell which case you are in, and then solving it with simple multiply-and-divide steps.
Let’s Break It Down
Before we start, let us quickly refresh the idea of a proportional relationship from Proportional Reasoning – 1, because everything here builds on it.
Checking if two ratios are proportional: cross-multiplication
Reducing both ratios to simplest form works, but there is a faster test. It is called cross-multiplication.
Suppose Viswanath makes idli batter with 6 cups of rice and 3 cups of dal (ratio 6 : 3). Puneet uses 4 cups of rice and 2 cups of dal (ratio 4 : 2). Will their idlis taste the same? They will, if the two ratios are proportional.
Here is the trick. Write the ratios as two fractions: 6/3 and 4/2. Multiply across the equals sign — top-left times bottom-right, and bottom-left times top-right. If both answers match, the ratios are proportional.
The picture below shows the two cross products meeting in the middle.
So the general rule is short and worth remembering.
Two ratios a : b and c : d are proportional when their cross products match:
a × d = b × c
Notice why this works. Saying a/b = c/d is the same as saying the two fractions are equal. To compare two fractions, you bring them to the same value by cross-multiplying — that is just the fraction rule you already know, applied to ratios.
Mix A uses rice : dal = 8 : 5. Mix B uses rice : dal = 24 : 15. Will they taste the same — that is, are the ratios proportional?
- Write the cross products. Here a : b is 8 : 5 and c : d is 24 : 15. So a × d = 8 × 15, and b × c = 5 × 24.
- Work them out. 8 × 15 = 120. And 5 × 24 = 120.
- Compare. Both cross products are 120, so they are equal.
- Equal cross products means the ratios are proportional: 8 : 5 :: 24 : 15. Yes, the two mixes will taste the same.
Direct proportion: growing together
Now to the heart of the chapter. We start with the case where two quantities grow together.
Think again about idli batter. The recipe needs rice and dal in the ratio 2 : 1. If you want more batter, you add more of both, keeping that ratio. The table below shows a few amounts.
For 2 cups of rice you use 1 cup of dal. For 4 cups of rice, 2 cups of dal. For 6, then 3. For 8, then 4. Look what stays the same: in every row, dal ÷ rice = 1/2.
This is direct proportion. When one quantity goes up, the other goes up by the same factor. Double the rice, the dal doubles too. Triple it, the dal triples too.
Here is the key fact, and the “why” behind it. Because both quantities always change by the same factor, their ratio never changes. So if you divide one by the other, you always get the same number. We call that fixed number the constant of proportionality, written k.
Two quantities x and y are in direct proportion when their quotient is always the same:
y ÷ x = k (a constant)
Equivalently, y = k × x.
There is a beautiful way to see direct proportion. If you plot the pairs (rice, dal) as points on a graph, they all land on a straight line that passes through the origin (the corner point 0, 0). Figure 3.2 shows both the table and this graph together.
Why does the line pass through the origin? Because if you use 0 rice, you use 0 dal. No batter at all. That point (0, 0) is always on a direct-proportion graph, and the steady ratio keeps the line straight.
The everyday way to use direct proportion is the unitary method — “unit” meaning one. You first find the value for one unit (by dividing), then scale up to however many you want (by multiplying).
Let us see it on a real problem.
5 workers can move 4500 bricks in a day. How many bricks can 20 workers move in a day, at the same rate?
- Decide the type. More workers means more bricks moved. Both go up together, so this is direct proportion.
- Find the value for ONE worker (divide). One worker moves 4500 ÷ 5 = 900 bricks in a day.
- Scale up to 20 workers (multiply). 20 workers move 900 × 20 = 18000 bricks.
- So 20 workers can move 18000 bricks in a day.
Figure 3.3 lays out those two steps as a simple flow, so the “find one, then find many” habit sticks.
Inverse proportion: trading off
Now the opposite case — and the one students most often confuse. Sometimes when one quantity goes up, the other goes down.
Here is the classic example. Puneeth’s father travels from Lucknow to Kanpur. The distance is fixed. He can go at different speeds, and the time changes. The table below shows it.
Walking at 5 km/h takes 18 hours. By bicycle at 15 km/h it takes 6 hours. By motorcycle at 30 km/h, 3 hours. By car at 60 km/h, just 1.5 hours.
Look carefully. As the speed goes up, the time goes down. Faster means you spend less time on the road. That makes good sense — if you move quicker, the same journey is over sooner.
But there is something more precise hiding here. Going by bicycle (15 km/h) is 3 times faster than walking (5 km/h), because 15 ÷ 5 = 3. And the time drops from 18 hours to 6 hours — exactly 3 times smaller, because 18 ÷ 6 = 3. The speed went up by a factor of 3, and the time went down by the same factor of 3.
This is inverse proportion. When one quantity changes by a factor n, the other changes by the inverse factor 1/n (the upside-down version). Up by 3 on one side, down to 1/3 on the other.
And here is the “why” that makes it click, plus the key fact. In every row of the table, multiply speed by time:
5 × 18 = 90
15 × 6 = 90
30 × 3 = 90
60 × 1.5 = 90
Every product is 90. That number is the distance between the two cities (90 km) — and the distance never changes, no matter how you travel. That is why the product stays fixed.
Two quantities x and y are in inverse proportion when their product is always the same:
x × y = k (a constant)
So in inverse proportion the product is fixed (unlike direct, where the quotient is fixed). If you know two pairs of values (x₁, y₁) and (x₂, y₂), then because both products equal the same k:
x₁ × y₁ = x₂ × y₂
This one equation solves almost every inverse-proportion problem. You will use it again and again.
There is also a tidy way to see inverse proportion on a graph. If you plot the pairs, they do not make a straight line. They make a downward curve that swoops from high values down towards the axes but never touches them. Figure 3.4 shows the table and this curve side by side, so you can compare it with the straight line of direct proportion.
Let us solve an inverse problem with the product rule.
20 workers take 4 days to lay a road. How many days will 10 workers take to lay the same road, working at the same rate?
- Decide the type. Fewer workers means the same work takes longer — more days. One goes down, the other goes up. So this is inverse proportion.
- Use the product rule: workers × days stays constant. So x₁ × y₁ = x₂ × y₂, which is 20 × 4 = 10 × y₂.
- Work out the left side: 20 × 4 = 80. So 80 = 10 × y₂.
- Divide both sides by 10: y₂ = 80 ÷ 10 = 8. So 10 workers take 8 days. (Notice: halving the workers doubled the days — exactly the inverse-factor pattern.)
The same product rule cracks pumps filling a tank, food provisions lasting a number of days, and machines making toys. Whenever “more of one means less of the other,” reach for x₁ × y₁ = x₂ × y₂.
2 pumps can fill a tank in 18 hours. If we add 2 more identical pumps, how long will the 4 pumps take to fill the same tank?
- Count the pumps now: 2 + 2 = 4 pumps. More pumps means less time, so this is inverse proportion.
- Use the product rule: pumps × hours stays constant. So 2 × 18 = 4 × x, where x is the new time.
- Left side: 2 × 18 = 36. So 36 = 4 × x.
- Divide both sides by 4: x = 36 ÷ 4 = 9. So 4 pumps fill the tank in 9 hours.
Telling the two apart
So the whole game is: is this direct or inverse? Get that right and the rest is easy. Figure 3.5 puts the two side by side so the contrast is sharp.
A quick test you can run in your head: ask “when the first quantity goes up, does the second go up or down?”
- Goes up too → direct (the quotient y ÷ x is fixed).
- Goes down → inverse (the product x × y is fixed).
Here is the side-by-side summary in a table.
| Direct proportion | Inverse proportion | |
|---|---|---|
| When x goes up, y… | goes up by the same factor | goes down by the same factor |
| What stays constant | the quotient y ÷ x = k | the product x × y = k |
| Key equation | y = k × x | x₁ × y₁ = x₂ × y₂ |
| Graph | straight line through origin | downward curve |
| Example | more workers, more bricks | more workers, fewer days |
A car covers a fixed distance. As its speed increases, the time taken decreases by the same factor. Is speed-and-time a direct or an inverse proportion?
It is an inverse proportion. When one quantity (speed) goes up, the other (time) goes down by the same factor. Their product, speed × time, stays constant — and that constant is the fixed distance. So this is inverse, not direct.
A trickier one: people working together
Sometimes a problem mixes the ideas. Suppose Ram can cut a pile of vegetables in 1 hour, and Shyam can cut the same pile in 1.5 hours. If they work together, how long will it take?
The clever move is to think in terms of work done in one hour, not total time. Count the whole job as 1 unit of work.
- Ram finishes in 1 hour, so in 1 hour he does 1 unit of work.
- Shyam finishes in 1.5 hours, so in 1 hour he does 1 ÷ 1.5 = 2/3 units of work.
Together, in one hour they do 1 + 2/3 = 5/3 units. Now this last step is a direct proportion: the amount of work done is directly proportional to the time spent. More time, more work — both go up together.
Ram cuts the vegetables in 1 hour, Shyam in 1.5 hours. Working together, how long do they take? (Count the whole job as 1 unit of work.)
- Find each person’s work in 1 hour. Ram does 1 unit per hour. Shyam does 1 ÷ 1.5 = 2/3 unit per hour.
- Add them. Together they do 1 + 2/3 = 5/3 units of work in 1 hour.
- Work and time are directly proportional. So 5/3 units take 1 hour means 1 unit takes 1 ÷ (5/3) hours. To divide by 5/3, flip and multiply: 1 × 3/5 = 3/5.
- So together they finish the whole job (1 unit) in 3/5 hour — that is 36 minutes. (Sensibly, this is less than Ram’s own 1 hour, since two people are faster than one.)
Common Mistakes
These three slips cost the most marks. Read them once and dodge them for good.
Whenever two quantities are linked, you can just multiply across like a direct proportion.
Direct-proportion problems are the first kind students meet, and the 'find one, then multiply up' steps feel so natural that they get applied to every problem out of habit, without first checking which way the second quantity moves.
First check the direction. If one quantity goes UP while the other goes DOWN, it is inverse, and you must keep the PRODUCT constant (x₁ × y₁ = x₂ × y₂), not the quotient. Setting up an inverse problem like a direct one gives an answer that is upside-down — too big where it should be small.
In every proportion, the same thing stays constant.
Both direct and inverse proportion have 'a constant k', so it is easy to remember that something is fixed but forget that it is a DIFFERENT something in each case.
In direct proportion the QUOTIENT y ÷ x is constant. In inverse proportion the PRODUCT x × y is constant. Picking the wrong one to hold fixed wrecks the whole solution. Decide direct-or-inverse first, then you know whether to keep the quotient or the product the same.
More workers (or more pumps, or more machines) always means the job takes more time.
Bigger numbers feel like they should give bigger answers, so 'more workers' seems like it should lead to 'more days' — but that mixes up the two quantities, since it is the same fixed job being shared.
For a FIXED job, more workers means LESS time, because they share the work. That is inverse proportion. Always ask whether the total job is fixed; if it is, adding helpers brings the time DOWN, not up.
Quick Check
Try these four. Each one tests an idea from above.
Which pair of quantities is in INVERSE proportion?
In a direct proportion, what stays constant?
Are the ratios 9 : 6 and 12 : 8 proportional? (Use cross-multiplication.)
6 workers build a wall in 8 days. If only 4 workers are available, how many days will the same wall take?
Practice Problems
Try each one yourself first. Only then tap to see the full solution.
Easy
If 24 pencils cost ₹120, how much will 20 such pencils cost?
More pencils cost more money, so this is direct proportion. First find the cost of ONE pencil (divide): ₹120 ÷ 24 = ₹5 per pencil. Now find the cost of 20 pencils (multiply): ₹5 × 20 = ₹100. So 20 pencils cost ₹100.
Check by cross-multiplication whether 7 : 4 and 21 : 12 are proportional.
Write the cross products. Here a : b is 7 : 4 and c : d is 21 : 12. a × d = 7 × 12 = 84. b × c = 4 × 21 = 84. Both cross products are 84, so they are equal. Equal cross products means the ratios are proportional: 7 : 4 :: 21 : 12.
Medium
A school has food provisions to feed 80 students for 15 days. If 20 more students join, for how many days will the provisions last?
First count the students now: 80 + 20 = 100 students. More students eat the same food faster, so it lasts fewer days. This is inverse proportion. Keep the product constant: students × days stays the same. So 80 × 15 = 100 × x, where x is the new number of days. Left side: 80 × 15 = 1200. So 1200 = 100 × x. Divide both sides by 100: x = 1200 ÷ 100 = 12. The provisions will last 12 days.
A school has 8 periods a day, each 45 minutes long. If the school changes to 9 periods a day but keeps the same total school time, how long is each period now?
First find the total school time: 8 × 45 = 360 minutes. This total stays the same. More periods in the same total time means each period is shorter, so this is inverse proportion. Keep the product constant: periods × minutes-per-period stays the same. So 8 × 45 = 9 × x, which is 360 = 9 × x. Divide both sides by 9: x = 360 ÷ 9 = 40. Each period is now 40 minutes long.
A car takes 2 hours to reach a place at a speed of 60 km/h. How long will it take at 80 km/h?
The distance is fixed, and faster speed means less time — inverse proportion. Keep the product constant: speed × time stays the same. So 60 × 2 = 80 × x, where x is the new time. Left side: 60 × 2 = 120 (this is the distance, 120 km). So 120 = 80 × x. Divide both sides by 80: x = 120 ÷ 80 = 1.5. The car will take 1.5 hours (1 hour 30 minutes).
Challenge
A factory needs 42 machines to make a fixed number of toys in 63 days. How many machines are needed to make the same number of toys in 54 days?
The number of toys is fixed. Fewer days to do the same job means more machines are needed, so this is inverse proportion. Keep the product constant: machines × days stays the same. So 42 × 63 = x × 54, where x is the number of machines needed. Left side: 42 × 63 = 2646. So 2646 = x × 54. Divide both sides by 54: x = 2646 ÷ 54 = 49. So 49 machines are needed to finish in 54 days. (Sensibly, fewer days needed more machines.)
A small pump fills a tank in 3 hours; a large pump fills the same tank in 2 hours. If both pumps run together, how long will the tank take to fill?
Think in terms of work done in 1 hour. Count the whole tank as 1 unit of work. The small pump fills it in 3 hours, so in 1 hour it does 1/3 of the tank. The large pump fills it in 2 hours, so in 1 hour it does 1/2 of the tank. Together in 1 hour they do 1/3 + 1/2. Make the denominators match: 2/6 + 3/6 = 5/6 of the tank per hour. Work and time are directly proportional. If 5/6 of the tank takes 1 hour, then the whole tank (1 unit) takes 1 ÷ (5/6) hours. To divide by 5/6, flip and multiply: 1 × 6/5 = 6/5 hours. So together they fill the tank in 6/5 hours, which is 1 hour and 12 minutes.
Summary
- A ratio compares quantities (like rice : dal = 2 : 1); two ratios are proportional when they describe the same relationship.
- To test if two ratios are proportional, use cross-multiplication: a : b and c : d are proportional when a × d = b × c.
- In direct proportion, both quantities change by the same factor (double one, the other doubles). The quotient y ÷ x = k stays constant, and the graph is a straight line through the origin.
- In inverse proportion, one quantity goes up as the other goes down by the same factor. The product x × y = k stays constant (so x₁ × y₁ = x₂ × y₂), and the graph is a downward curve.
- To tell them apart, ask: when the first quantity goes up, does the second go up (direct) or down (inverse)?
- The unitary method solves direct problems: find the value for one unit by dividing, then multiply up.
- For “working together” problems, add up the work each does in one hour, then use direct proportion to find the total time.
What’s Next
You can now read the relationship between two changing quantities and put exact numbers on it — a skill you will use far beyond this classroom, every time you cook, shop, travel, or build.
Next we return to shapes. The following chapter is Exploring Some Geometric Themes, where you will look more closely at angles, lines, and the neat patterns that geometry hides in plain sight. See you there!
Frequently Asked Questions
What is the difference between direct and inverse proportion?
In direct proportion, both quantities change the same way — when one doubles, the other also doubles, and their quotient y divided by x stays constant. In inverse proportion, they change opposite ways — when one doubles, the other halves, and their product x times y stays constant. Direct grows together; inverse trades off.
How do you test if two ratios are proportional?
Use cross multiplication. For the ratios a to b and c to d, multiply a by d and multiply b by c. If the two cross products are equal, the ratios are proportional. For example, 6 to 3 and 4 to 2 are proportional because 6 times 2 equals 12 and 3 times 4 equals 12, and both are 12.
What is the unitary method?
The unitary method solves proportion problems in two steps. First you find the value for one unit by dividing. Then you find the value for the number you want by multiplying. For example, if 5 workers move 4500 bricks, one worker moves 4500 divided by 5 equals 900, so 20 workers move 900 times 20 equals 18000 bricks.
How do you know if a problem is inverse proportion?
Ask what happens to the second quantity when the first goes up. If the second goes down by the same factor, it is inverse proportion. More workers means fewer days, faster speed means less time, more pumps means less filling time. In every inverse case the product of the two quantities stays the same.
What stays constant in direct and in inverse proportion?
In direct proportion the quotient stays constant, so y divided by x equals a fixed number k. In inverse proportion the product stays constant, so x times y equals a fixed number k. Knowing which one is fixed tells you which kind of proportion you are dealing with and how to solve it.