Area
Why This Matters
Think about colouring a rangoli. You spread coloured powder evenly over a shape on the floor. A bigger shape needs more powder. A smaller shape needs less.
How much powder you need depends on how much flat space the shape covers. That flat space is what we call area.
Area is everywhere once you look. How much paint to cover a wall. How much cloth to stitch a kurta. How much grass seed for a park. How much tile to lay on a floor. A shopkeeper buying a piece of land pays by its area. A farmer thinks about the area of a field. Even the screen you are reading this on has an area.
For a simple rectangle, finding area is easy — you may already know length × width. But real shapes are not always neat rectangles. Fields are slanted. Plots have odd shapes. A roof might be a triangle or a trapezium.
This chapter does something powerful. It shows you how to find the area of any flat shape — parallelogram, triangle, trapezium, rhombus, or a five-sided plot — and, more importantly, why each formula is true. You will not just memorise formulas. You will see where they come from, by cutting shapes up and rearranging the pieces. That way you will remember them for life, not just for the exam.
The Big Idea
Area is the amount of flat space a shape covers. We measure it by counting how many unit squares (squares of side 1 cm) fit inside the shape. For a rectangle, that count is simply length × width. The clever idea of this whole chapter is that every other shape can be turned into a rectangle or built from triangles by cutting and rearranging its pieces — and rearranging never changes the area. From this one idea, all the area formulas follow: parallelogram = base × height, triangle = ½ × base × height, trapezium = ½ × (a + b) × h, and any polygon = a sum of triangles.
Let’s Break It Down
First, what does “area” really mean?
Before any formulas, let us be clear what we are measuring. We will lean on this everywhere, so here is a quick refresher.
Figure 7.1 shows this packing of unit squares for a 5 cm by 3 cm rectangle.
One quick warning, because students mix these up. A bigger perimeter does not always mean a bigger area. You can have two shapes where one has a longer boundary but covers less flat space. Perimeter measures the edge; area measures the inside. They are different things.
A rectangle is 6 cm long and 4 cm wide. What is its area, and in what units?
Area = length × width = 6 × 4 = 24. The units are square centimetres, so the area is 24 cm². Remember area is always in square units, never plain cm.
The area of a triangle — half of a rectangle
Here is the first big jump. Take any rectangle and draw one diagonal across it. The diagonal cuts the rectangle into two equal triangles. They are exactly the same — one is just the other flipped over.
So each triangle covers exactly half the rectangle. If the rectangle is base wide and height tall, its area is base × height. Half of that is the area of one triangle.
This is the single most useful area fact in the chapter, so let us see why it works for every triangle, not just the neat right-angled one inside a rectangle.
The trick is to take a second copy of the triangle, turn it upside down, and fit it against the first. The two copies always join to form a parallelogram. Figure 7.2 shows this.
So no matter what the triangle looks like — tall, thin, slanted, or wide — two copies make a parallelogram, and one triangle is half of it.
Area of a triangle = ½ × base × height
The base is any one side you choose. The height is the perpendicular distance from that side up to the opposite corner.
The word perpendicular is important. The height must go straight across at a right angle to the base, not along a slanted side. We will come back to this — it is the number-one mistake students make.
Let us use the formula.
A triangle has a base of 8 cm. The perpendicular height from that base to the opposite corner is 5 cm. Find its area.
- Write down the formula: Area = ½ × base × height.
- Put in the numbers. The base is 8 cm and the height is 5 cm. So Area = ½ × 8 × 5.
- Work it out step by step. First ½ × 8 = 4. Then 4 × 5 = 20.
- So the area of the triangle is 20 cm².
Sometimes you can run the formula backwards to find a missing length. Since the area of a triangle can be written using any side as the base, two different base-and-height pairs give the same area. That lets us find an unknown height.
In triangle ABC, the base BC = 6 cm and the height to it is 5 cm. A different height, BY, is dropped onto side AC, which is 4 cm long. Find BY.
- First find the area using the pair we know fully. Area = ½ × BC × height = ½ × 6 × 5 = 15 cm².
- The same triangle has the same area no matter which side we call the base. Using AC as the base, Area = ½ × AC × BY = ½ × 4 × BY = 2 × BY.
- Both expressions give the same area, so 2 × BY = 15.
- Divide both sides by 2: BY = 15 ÷ 2 = 7.5 cm.
The area of a parallelogram — cut and slide into a rectangle
A parallelogram is a four-sided shape with both pairs of opposite sides parallel. It looks like a rectangle that has been pushed over to one side, so it leans.
Because it leans, we cannot just multiply two sides. But we can do something clever: cut a piece off one end and slide it to the other end to make a rectangle. Since we only moved a piece — we did not add or remove anything — the area stays the same. This cutting-and-rearranging move has a name: dissection.
Here is the cut. Drop a perpendicular line from the top corner straight down to the base. This cuts off a right-angled triangle. Slide that triangle across to the other side, and the parallelogram becomes a neat rectangle. Figure 7.3 shows the whole move.
The cut piece fits the gap on the other side perfectly. (You can prove the two triangles are identical using the RHS rule for congruent triangles, but you can also just try it with a paper cut-out and see.) So:
Area of a parallelogram = base × height
Here base is one side, and height is the perpendicular distance from that side across to the opposite parallel side.
Notice you can pick either pair of parallel sides as the base, as long as you use the matching perpendicular height. Both choices give the same area.
A parallelogram has a base of 7 cm. The perpendicular height to that base is 4 cm. Find its area.
- Write the formula: Area = base × height.
- Put in the numbers. Base = 7 cm, height = 4 cm. So Area = 7 × 4.
- Multiply: 7 × 4 = 28.
- So the area of the parallelogram is 28 cm².
Watch out: height is the perpendicular distance, not the slant side
This is the trap that catches the most students, so let us look at it carefully. A parallelogram has a base, and it also has a slanted side. The slanted side is not the height.
The height is the perpendicular distance — the straight-across distance between the two parallel sides, measured at a right angle. The slanted side is longer than this perpendicular distance, because it goes across and up at the same time. Figure 7.4 makes the difference clear.
So whenever a problem gives you both the slant side and the perpendicular height, use the height. The slant side is often given just to test whether you know the difference.
A parallelogram has a base of 10 cm, a slanted side of 6 cm, and a perpendicular height of 5 cm. What is its area?
Use the perpendicular height, not the slant side. Area = base × height = 10 × 5 = 50 cm². The 6 cm slant side is not used in the area at all — it is there to tempt you. The answer is 50 cm².
The area of a trapezium — split it into pieces you know
A trapezium is a four-sided shape with exactly one pair of parallel sides. Think of the cross-section of a dam wall, or a handbag shape: a wide bottom, a narrower top, and two slanted sides joining them.
The two parallel sides are usually different lengths. Call them a (the shorter one) and b (the longer one). The perpendicular distance between them is the height h.
How do we find the area? We use the same trick as always: split it into shapes we already know. Drop a perpendicular from each end of the top side straight down to the bottom side. This carves the trapezium into a rectangle in the middle and two right triangles on the sides. Figure 7.5 shows the split.
Now add the three pieces. The rectangle has width a (same as the top side) and height h, so its area is a × h. Each triangle has height h. If the two triangle bases are x and y, their areas are ½ × x × h and ½ × y × h.
Add them up:
Area = ½ × x × h + a × h + ½ × y × h
Now here is the neat finish. The bottom side b is made of the two triangle bases x and y plus the rectangle width a. So x + y + a = b, which means x + y = b − a. Substitute that in and tidy up, and the messy expression collapses into one clean formula:
Area of a trapezium = ½ × (sum of the parallel sides) × height = ½ × (a + b) × h
A lovely way to remember this: it is the average of the two parallel sides, (a + b) ÷ 2, multiplied by the height h. The trapezium behaves like a rectangle whose width is the average of its top and bottom.
Let us use it.
A trapezium has parallel sides of 10 cm and 14 cm. The perpendicular height between them is 6 cm. Find its area.
- Write the formula: Area = ½ × (a + b) × h.
- The parallel sides are a = 10 cm and b = 14 cm, and the height h = 6 cm. So Area = ½ × (10 + 14) × 6.
- Add inside the bracket first: 10 + 14 = 24. So Area = ½ × 24 × 6.
- Now multiply: ½ × 24 = 12, and 12 × 6 = 72. So the area is 72 cm².
The area of a rhombus — half the product of the diagonals
A rhombus is a special parallelogram where all four sides are equal — like a diamond on a playing card. Since it is a parallelogram, base × height still works for it.
But a rhombus has a neat extra feature: its two diagonals cross each other at right angles and cut each other exactly in half. This gives a second, often easier, formula based on the diagonals.
The diagonals split the rhombus into four small right-angled triangles. Rearranging them (another dissection) shows that the rhombus has the same area as a rectangle whose sides are one full diagonal and half the other diagonal. Multiplying those gives:
Area of a rhombus = ½ × (product of its diagonals) = ½ × d₁ × d₂
where d₁ and d₂ are the lengths of the two diagonals.
A rhombus has diagonals of 20 cm and 15 cm. Find its area.
- Write the formula: Area = ½ × d₁ × d₂.
- The diagonals are d₁ = 20 cm and d₂ = 15 cm. So Area = ½ × 20 × 15.
- Work it out: ½ × 20 = 10, and 10 × 15 = 150.
- So the area of the rhombus is 150 cm².
The area of any polygon — break it into triangles
Now the most powerful idea of all. What about a shape that is none of the above — a five-sided plot of land, or some odd many-sided figure?
The answer is simple and always works: break it into triangles. From one corner of the polygon, draw straight lines (diagonals) to every other corner. These lines cut the whole shape into triangles. Find the area of each triangle and add them all up. Figure 7.6 shows this for a pentagon.
So you never get stuck. Even the strangest straight-sided shape is just a collection of triangles in disguise.
The same idea works for composite shapes made of familiar pieces — say a rectangle with a triangle on top (like a simple house shape). You do not need a single formula. Just split the shape into a rectangle and a triangle, find each area, and add.
A shape is made of a rectangle 8 cm wide and 5 cm tall, with a triangle sitting on top of it. The triangle has the same 8 cm base and a height of 3 cm. Find the total area.
- Split the shape into two pieces you know: the rectangle and the triangle on top.
- Area of the rectangle = length × width = 8 × 5 = 40 cm².
- Area of the triangle = ½ × base × height = ½ × 8 × 3 = 12 cm².
- Add the two pieces: 40 + 12 = 52 cm². That is the total area of the composite shape.
Common Mistakes
These are the slips students make most often with area. Read them once and you will avoid them.
The height of a parallelogram or triangle is the length of its slanted side.
The slanted side is right there along the edge of the figure, and it does look like it goes from the base up to the top — so it feels like the natural thing to call the 'height'.
The height is the perpendicular distance — measured straight across at a right angle to the base — not the slanted edge. The slant side is longer than the perpendicular height, so using it makes the area too big. Always use the right-angled height in base × height and ½ × base × height.
Area is measured in plain cm or m, the same units as length.
We measure lengths in cm and m all the time, and area is found by multiplying two lengths — so it is easy to forget that multiplying two lengths changes the unit too.
Area is always in SQUARE units: cm², m², and so on. When you multiply 5 cm by 3 cm, the units multiply as well: cm × cm = cm². Writing an area as plain cm (the unit for perimeter or length) is wrong.
For a trapezium you multiply the two parallel sides together, or just use one of them.
The area of a rectangle is found by multiplying two sides, so students expect a trapezium to work the same way — pick two sides and multiply.
A trapezium has two DIFFERENT parallel sides, so you ADD them first and take the average. The formula is ½ × (a + b) × h: add the two parallel sides, then multiply by the height and halve. It is the average of the parallel sides times the height, not the two sides multiplied.
Quick Check
Try these. Each one checks an idea from the chapter.
A parallelogram has a base of 9 cm and a perpendicular height of 4 cm. What is its area?
Why is the area of a triangle equal to ½ × base × height?
A trapezium has parallel sides of 6 cm and 10 cm, and a height of 5 cm. What is its area?
How can you find the area of an unusual five-sided polygon?
Practice Problems
Try each one yourself first. Only then tap to see the full solution.
Easy
A triangle has a base of 12 cm and a perpendicular height of 5 cm. Find its area.
Use the triangle formula: Area = ½ × base × height. Put in the numbers: Area = ½ × 12 × 5. First ½ × 12 = 6. Then 6 × 5 = 30. So the area of the triangle is 30 cm².
A parallelogram has a base of 8 cm and a perpendicular height of 4.5 cm. Find its area.
Use the parallelogram formula: Area = base × height. Put in the numbers: Area = 8 × 4.5. Multiply: 8 × 4.5 = 36. So the area of the parallelogram is 36 cm².
A rhombus has diagonals of 12 cm and 16 cm. Find its area.
Use the rhombus formula: Area = ½ × d₁ × d₂. Put in the numbers: Area = ½ × 12 × 16. First ½ × 12 = 6. Then 6 × 16 = 96. So the area of the rhombus is 96 cm².
Medium
A trapezium has parallel sides of 9 cm and 13 cm, and a perpendicular height of 8 cm. Find its area.
Use the trapezium formula: Area = ½ × (a + b) × h. Add the parallel sides first: 9 + 13 = 22. So Area = ½ × 22 × 8. Now ½ × 22 = 11, and 11 × 8 = 88. So the area of the trapezium is 88 cm².
A parallelogram has a base of 10 cm, a slanted side of 7 cm, and a perpendicular height of 6 cm. Find its area. (Be careful which length you use!)
The area of a parallelogram is base × height, where height means the PERPENDICULAR height. So use the height 6 cm, not the slanted side 7 cm. Area = base × height = 10 × 6 = 60. So the area is 60 cm². The 7 cm slant side is not used at all — it is there to test you.
A quadrilateral ABCD has a diagonal AC = 22 cm. From B, a perpendicular of length 3 cm drops onto AC. From D, another perpendicular of length 3 cm drops onto AC, on the other side. Find the area of the quadrilateral. (Hint: the diagonal splits it into two triangles.)
The diagonal AC splits the quadrilateral into two triangles: ABC and ACD. Both triangles use AC = 22 cm as their base. Triangle ABC has height 3 cm (the perpendicular from B). Its area = ½ × 22 × 3 = 33 cm². Triangle ACD has height 3 cm (the perpendicular from D). Its area = ½ × 22 × 3 = 33 cm². Add the two triangles: 33 + 33 = 66. So the area of the quadrilateral is 66 cm².
Challenge
A field is shaped like a rectangle 18 m long and 10 m wide, with a triangular piece added on one short end. The triangle has the same 10 m base and a height of 6 m. Find the total area of the field.
Split the field into two known shapes: the rectangle and the triangle. Area of the rectangle = length × width = 18 × 10 = 180 m². Area of the triangle = ½ × base × height = ½ × 10 × 6 = 30 m². Add the two pieces: 180 + 30 = 210. So the total area of the field is 210 m². This is the “split into known shapes” method for any composite figure.
In triangle ABC, side BC = 6 cm and the perpendicular height to BC is 5 cm. A second perpendicular, BY, is dropped from B onto side AC, which is 4 cm long. Find the length of BY.
First find the area using the pair we know fully. Area = ½ × BC × height = ½ × 6 × 5 = 15 cm². The same triangle has the same area whichever side we call the base. Using AC as the base: Area = ½ × AC × BY = ½ × 4 × BY = 2 × BY. Both give the same area, so 2 × BY = 15. Divide both sides by 2: BY = 7.5 cm. So the length of BY is 7.5 cm.
Summary
- Area is the flat space a shape covers. We measure it by counting unit squares (squares of side 1 cm), and it is always in square units like cm² or m².
- Area of a rectangle = length × width. A square is a rectangle with equal sides, so its area is side × side.
- Area of a triangle = ½ × base × height. This is true because two copies of any triangle join to make a parallelogram, so one triangle is half of it.
- Area of a parallelogram = base × height. We get this by cutting a triangle off one end and sliding it across to make a rectangle (a dissection).
- The height always means the perpendicular distance — measured straight across at a right angle — not the slanted side. Using the slant side gives an answer that is too big.
- Area of a trapezium = ½ × (a + b) × h, where a and b are the two parallel sides and h is the perpendicular distance between them. It is the average of the parallel sides times the height.
- Area of a rhombus = ½ × (product of its diagonals) = ½ × d₁ × d₂.
- Any polygon can be split into triangles (and any composite shape into known pieces). Find each piece’s area and add them up.
What’s Next
That brings Ganita Prakash Part II — and your whole Class 8 maths journey — to a close. Look at how far you have come. You explored squares, cubes and powers; you learned the story of numbers and how we write them; you mastered quadrilaterals, number play, and the magic of distributing and factorising; you built up proportional reasoning; you uncovered fractions hiding in disguise; and now you can find the area of any flat shape and explain why every formula is true.
The thread running through all of it is the habit you just practised here: never accept a formula as a given. Take it apart, see where it comes from, and you will own it for life. That is exactly the thinking that the next stage of maths — Class 9 and beyond — will reward.
Want to revisit any chapter or move to another subject? Head back to your full list of topics here: Class 8 Maths. Well done finishing the book — you have earned it.
Frequently Asked Questions
What is the formula for the area of a parallelogram?
Area of a parallelogram = base × height. The height must be the perpendicular (straight-up) distance between the two parallel sides, not the slanted side. We get this formula by cutting a triangle off one end of the parallelogram and sliding it to the other end to make a rectangle of the same base and height.
Why is the area of a triangle half the base times the height?
Because a triangle is exactly half of a parallelogram. If you take a second copy of any triangle and turn it upside down, the two copies fit together to make a parallelogram with the same base and height. The parallelogram has area base times height, so one triangle is half of that, giving half times base times height.
What is the formula for the area of a trapezium?
Area of a trapezium = half × (sum of the parallel sides) × height. If the parallel sides are a and b, and the perpendicular distance between them is h, the area is ½ × (a + b) × h. You can prove it by splitting the trapezium into a rectangle and two right triangles and adding their areas.
How do you find the area of a shape that is not a standard figure?
Split it into shapes you already know — rectangles, triangles and trapeziums. Find the area of each piece, then add them up. Any polygon can be cut into triangles by drawing diagonals from one corner, so you can always find its area this way.
What is the difference between the height and the slant side of a parallelogram?
The height is the perpendicular distance between the two parallel sides — measured straight across at a right angle. The slant side is the actual slanted edge of the figure, which is longer. Only the perpendicular height goes into the area formula. Using the slant side gives an answer that is too big.